01-16-2008
How to print arguments along with spaces using awk
Hi All,
file_1.txt contains
aaa bbbb hhhh
vvvvv mmmmm iiiii
What i want is to search for the first coloumn of each line using awk.i.e as below:
awk '/aaa/ {printf(<>)}' file_1.txt
The print part (<>) should contain all the values(or coloumns ) in the particular line(here it is: bbbb hhhh) including the spaces between each arguments.Given that the "aaa" should not be printed.
In short my output after running the above awk should be
bbbb hhhh
If it is the "vvvv" am searching for then the result should be
mmmmm iiiii
Thanks in advance
JS
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