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Top Forums UNIX for Dummies Questions & Answers need some info about symbolic link and hard link Post 302156443 by frank_rizzo on Tuesday 8th of January 2008 06:26:58 AM
Old 01-08-2008
Quote:
Originally Posted by detective linux
i open terminal and join as root
and i wrote ln -s blah blah
then i wrote ls
i see red file called blah blah
but didn't understand what is this can some one explain and is this the way to read it ?
This should fail if blah already exists. If blah is a directory it will create the link in the directory.

Quote:
Originally Posted by detective linux
what if remove the orginal file of hard link can i still see the content of the file
if its the last reference to the file then the file will be removed.

Quote:
Originally Posted by detective linux
and can i try to make a hard link to a directory ? To a non-existent file
no

Quote:
Originally Posted by detective linux
another more questions hope not one get angry coze i ask much

what if i try to change the permissions of the original file with chmod, or update its modification time with touch is there is something gunna happen for the links
the links all point to the same file so updating the permissions will appear like all links were changed. you cannot however change the permissions of a symbolic link.
 

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SHELL-QUOTE(1)						User Contributed Perl Documentation					    SHELL-QUOTE(1)

NAME
shell-quote - quote arguments for safe use, unmodified in a shell command SYNOPSIS
shell-quote [switch]... arg... DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands or files with embedded white space or shell globbing characters safely. Here are a few examples. EXAMPLES
ssh preserving args When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and passes them to "$SHELL -c". This doesn't work as intended: ssh host touch 'hi there' # fails It creates 2 files, hi and there. Instead, do this: cmd=`shell-quote touch 'hi there'` ssh host "$cmd" This gives you just 1 file, hi there. process find output It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote: eval set -- `find -type f -print0 | xargs -0 shell-quote --` debug shell scripts shell-quote is better than echo for debugging shell scripts. debug() { [ -z "$debug" ] || shell-quote "debug:" "$@" } With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can. save a command for later shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are things the user can't pass through), you can do something like this: user_switches= while [ $# != 0 ] do case x$1 in x--pass-through) [ $# -gt 1 ] || die "need an argument for $1" user_switches="$user_switches "`shell-quote -- "$2"` shift;; # process other switches esac shift done # later eval "shell-quote some-command $user_switches my args" OPTIONS
--debug Turn debugging on. --help Show the usage message and die. --version Show the version number and exit. AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions. AUTHOR
Roderick Schertler <roderick@argon.org> perl v5.16.3 2010-06-11 SHELL-QUOTE(1)
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