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Top Forums UNIX for Dummies Questions & Answers Any simple method to check date format (YYDDD)? Post 302154876 by ganapati on Wednesday 2nd of January 2008 08:41:40 AM
Old 01-02-2008
Error

Sorry Vino but thanks,

My question is for the format of the date (YYDDD). i.e,
  1. YYDDD field should not be blank
  2. YY should be only from 00-99, not any other charecters and come first before DDD.
  3. DDD should be from 001-365 for normal years and 001-366 for leap years. This should come after YY

Iam looking for simpler code to accomplish this.

Thanks again,
Ganapati
 

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TIME(2) 						     Linux Programmer's Manual							   TIME(2)

NAME
time - get time in seconds SYNOPSIS
#include <time.h> time_t time(time_t *t); DESCRIPTION
time returns the time since the Epoch (00:00:00 UTC, January 1, 1970), measured in seconds. If t is non-NULL, the return value is also stored in the memory pointed to by t. RETURN VALUE
On success, the value of time in seconds since the Epoch is returned. On error, ((time_t)-1) is returned, and errno is set appropriately. ERRORS
EFAULT t points outside your accessible address space. NOTES
POSIX.1 defines seconds since the Epoch as a value to be interpreted as the number of seconds between a specified time and the Epoch, according to a formula for conversion from UTC equivalent to conversion on the naive basis that leap seconds are ignored and all years divisible by 4 are leap years. This value is not the same as the actual number of seconds between the time and the Epoch, because of leap seconds and because clocks are not required to be synchronised to a standard reference. The intention is that the interpretation of sec- onds since the Epoch values be consistent; see POSIX.1 Annex B 2.2.2 for further rationale. CONFORMING TO
SVr4, SVID, POSIX, X/OPEN, BSD 4.3 Under BSD 4.3, this call is obsoleted by gettimeofday(2). POSIX does not specify any error conditions. SEE ALSO
ctime(3), date(1), ftime(3), gettimeofday(2) Linux 2.0.30 1997-09-09 TIME(2)
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