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Top Forums UNIX for Dummies Questions & Answers problem in script involving month arithmetic Post 302154568 by fpmurphy on Monday 31st of December 2007 06:45:16 AM
Old 12-31-2007
Code:
typeset -i month=`date +"%m"`

if [ $month -eq 3 -o $month -eq 6 -o $month -eq 9 -o $month -eq 12 ]
then
   inc_flg=1
else
   inc_flg=2
fi

 

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CAL(1)							    BSD General Commands Manual 						    CAL(1)

NAME
cal -- displays a calendar SYNOPSIS
cal [-smjy13] [[month] year] DESCRIPTION
Cal displays a simple calendar. If arguments are not specified, the current month is displayed. The options are as follows: -1 Display single month output. (This is the default.) -3 Display prev/current/next month output. -s Display Sunday as the first day of the week. (This is the default.) -m Display Monday as the first day of the week. -j Display Julian dates (days one-based, numbered from January 1). -y Display a calendar for the current year. A single parameter specifies the year (1 - 9999) to be displayed; note the year must be fully specified: ``cal 89'' will not display a calen- dar for 1989. Two parameters denote the month (1 - 12) and year. If no parameters are specified, the current month's calendar is displayed. A year starts on Jan 1. The Gregorian Reformation is assumed to have occurred in 1752 on the 3rd of September. By this time, most countries had recognized the ref- ormation (although a few did not recognize it until the early 1900's.) Ten days following that date were eliminated by the reformation, so the calendar for that month is a bit unusual. HISTORY
A cal command appeared in Version 6 AT&T UNIX. OTHER VERSIONS
Several much more elaborate versions of this program exist, with support for colors, holidays, birthdays, reminders and appointments, etc. For example, try the cal from http://home.sprynet.com/~cbagwell/projects.html or GNU gcal. BSD
June 6, 1993 BSD
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