12-19-2007
Quote:
Originally Posted by
idle
the last field may pose you issues though: 20071254
Man - December is going to be a long month this year!
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1. UNIX for Dummies Questions & Answers
Hi,
I want to know how to change this string to date format
20061102122042 to 02-11-2006 12:20:42
or 02-Nov-2006 12:20:42
Please let me know at the earliest.Thanks in advance.
Regards,
Preetham R. (3 Replies)
Discussion started by: preethgideon
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2. Shell Programming and Scripting
Hi All,
this is my second post, last post reply was very helpful.
I have a data that has date in DD/MM/YYYY (07/11/2008) format i want to replace the backslash by a dot(.) so that my awk script can read it inside the C shell script that i have written.
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3. Solaris
dear members,
ls -l
drwxr-xr-x 40 root sys 1024 Jul 11 22:19 usr
drwxr-xr-x 43 root sys 1024 Feb 1 2009 var
i am using solaris 10
is that possibe to do
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4. Shell Programming and Scripting
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Hi guys,
I have a text file with lots of lines like this:
MCOGT23R27815 27/07/07 27/05/09
SO733AM0235 30/11/07 30/11/10
NL123403N 04/03/08 04/03/11
0747AM7474 04/04/08 04/04/11
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6. Shell Programming and Scripting
Hi,
Please can I have some command to get yesterday in YYMMDD format?
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7. Shell Programming and Scripting
Dear Friends,
Need your help once again,
I have a variable ( e.g. ${i}) whoch has date in MM/DD/YYYY (E.g. 12/31/2011) format.
I want to change it to DD/MM/YYYY (e.g. 31/12/2011) format.
Request you to guide me as we are unable to do the same.
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Anu. (1 Reply)
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8. Shell Programming and Scripting
Hi,
I have the variable "$date_update" in that form:
2011-12-31T13:00:09Z and I would like to change it to
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Jurgen (4 Replies)
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Hi all,
I have a file that every line starts with the date and time. The format is like YYYYMMDDHHMM and I woulk like to change it to MM/DD/YY<space>HH:MM.
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10. Shell Programming and Scripting
Hi,
I was looking for a script to change the date from one format to other. A search in the forum gave me the below script as a result.
#! /bin/ksh
format=YYYYMMDD
YEAR=${format%????}
DAY=${format#??????}
MON=${format#$YEAR}
MON=${MON%$DAY}
echo $MON/$DAY/$YEAR
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CAL(1) BSD General Commands Manual CAL(1)
NAME
cal -- displays a calendar
SYNOPSIS
cal [-smjy13] [[[day] month] year]
DESCRIPTION
Cal displays a simple calendar. If arguments are not specified, the current month is displayed. The options are as follows:
-1 Display single month output. (This is the default.)
-3 Display prev/current/next month output.
-s Display Sunday as the first day of the week.
-m Display Monday as the first day of the week.
-j Display Julian dates (days one-based, numbered from January 1).
-y Display a calendar for the current year.
-V Display version information and exit.
A single parameter specifies the year (1 - 9999) to be displayed; note the year must be fully specified: ``cal 89'' will not display a calen-
dar for 1989. Two parameters denote the month (1 - 12) and year. Three parameters denote the day (1-31), month and year, and the day will
be highlighted if the calendar is displayed on a terminal. If no parameters are specified, the current month's calendar is displayed.
A year starts on Jan 1. The first day of the week is determined by the locale.
The Gregorian Reformation is assumed to have occurred in 1752 on the 3rd of September. By this time, most countries had recognized the ref-
ormation (although a few did not recognize it until the early 1900's.) Ten days following that date were eliminated by the reformation, so
the calendar for that month is a bit unusual.
HISTORY
A cal command appeared in Version 6 AT&T UNIX.
OTHER VERSIONS
Several much more elaborate versions of this program exist, with support for colors, holidays, birthdays, reminders and appointments, etc.
For example, try the cal from http://home.sprynet.com/~cbagwell/projects.html or GNU gcal.
AVAILABILITY
The cal command is part of the util-linux-ng package and is available from ftp://ftp.kernel.org/pub/linux/utils/util-linux-ng/.
BSD
June 6, 1993 BSD