Bash/AWK Newbie taking on more than he can chew. Post: 302152283

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Hi there, I am a student and currently working on a project. I have a file that contains about 50 filenames. (1.txt, 2.txt, 3.txt ...). I would like to know how can I store these filenames into a variable using a loop? I would appreciate if anyone can help me. Thank You. Regards, Bib

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I'm in .profile. I want to export a directory ( export MY_TOOL_HOME=/tools/my tool". Unfortunately for me, the directory I want to export to has a space in its name. So when I try to cd $MY_TOOL_HOME, i get a No such file or directory at the command line... thanks for the help

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Hi, I'm very new to bash scripting and Linux in general. I'm running Ubuntu Server 10.04 and trying to write a bash script to launch a program. In doing so, I've come across a couple of things that I obviously don't understand. Here is a short script that exemplifies those things: ...

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Looking for help with parsing file contents in bash [newbie]

Hi I'm just messing around with bash and trying to learn it because I have a course next semester dealing with OS design where we need to know how to use SSH client and either bash or ksh. I've never done shell scripting before. I just started today and I was wondering how parsing files...

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awk solution for taking bins

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Hi, i want to print 2nd column value with the below script. I need to take input of the string i need to search in that file and file name. How can i take these two as inputs? using read command? Getting error for below script. echo "enter SID" read SID echo "enter filename" read filename...

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Bash scripting - Newbie

Hi all, I have drill to do and I'll very appreciate your help: Please create a simple CSV file as follow (3 columns and 4 rows): A,B,C A,”B,C”,D “A,B”,C,D o A,B,”C,D” - Please refer to the comma between the quotation marks as a parameter and not as a separator. - Please provide...

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Newbie needs help with some bash scripting

Please bear with me, I'm a beginner but have had some experience and decent knowledge to understand things as I read them and I'm in the process of trying to learn more. I recently inherited a UNIX server which has a bash script which is part of a crontab schedule that needs to be modified (or...

LEARN ABOUT LINUX

bashbug

BASHBUG(1)							      bashbug								BASHBUG(1)

NAME

       bashbug - report a bug in bash

SYNOPSIS

       bashbug [--help] [--version] [bug-report-email-addresses]

DESCRIPTION

       bashbug is a utility for reporting bugs in Bash to the maintainers.

       bashbug will start up your preferred editor with a preformatted bug report template for you to fill in. Save the file and quit the editor
       once you have completed the missing fields.  bashbug will notify you of any problems with the report and ask for confirmation before
       sending it. By default the bug report is mailed to both the GNU developers and the Debian Bash maintainers. The recipients can be changed
       by giving a comma separated list of bug-report-email-addresses.

       If you invoke bashbug by accident, just quit your editor. You will always be asked for confirmation before a bug report is sent.

OPTIONS

       --help
	      Show a brief usage message and exit.

       --version
	      Show the version of bashbug and exit.

       bug-report-email-addresses
	      Comma separated list of recipients' email addresses. By default the report is mailed to both the GNU developers and the Debian Bash
	      maintainers.

ENVIRONMENT

       DEFEDITOR
	      Editor to use for editing the bug report.

       EDITOR
	      Editor to use for editing the bug report (overridden by DEFEDITOR).

SEE ALSO

       bash(1), reportbug(1), update-alternatives(8) for preferred editor.

AUTHOR

       This manual page was written by Christer Andersson <klamm@comhem.se> for the Debian project (but may be used by others).

GNU Bash 3.1							 11 December 2007							BASHBUG(1)

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