Sponsored Content
Top Forums Shell Programming and Scripting What to do when mtime doesn't work? Post 302151866 by bbbngowc on Monday 17th of December 2007 08:43:43 PM
Old 12-17-2007
Quote:
Originally Posted by reborg
Or touch a file at the end of each collection and simply gather the files newer than the file you touched the next time, then touch the file again.
So at the end of the script, have the script touch the same file again?
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Why doesn't this work?

cat .servers | while read LINE; do ssh jason@$LINE $1 done exit 1 ./command.ksh "ls -l ~jason" Why does this ONLY iterate on the first server in the list? It's not doing the command on all the servers in the list, what am I missing? Thanks! JP (2 Replies)
Discussion started by: jpeery
2 Replies

2. UNIX for Advanced & Expert Users

chown doesn't work

Hi unix gurus, I am facing problem with chown command. I am not able to change the owner of any file in my home. It gives error "not owner", though I own the file(as ls shows). What could be the reason? Is it possible that usage chown can be disabled for users. $ $ ls -l total 2... (10 Replies)
Discussion started by: shriashishpatil
10 Replies

3. UNIX for Dummies Questions & Answers

Script doesn't work, but commands inside work

Howdie everyone... I have a shell script RemoveFiles.sh Inside this file, it only has two commands as below: rm -f ../../reportToday/temp/* rm -f ../../report/* My problem is that when i execute this script, nothing happened. Files remained unremoved. I don't see any error message as it... (2 Replies)
Discussion started by: cheongww
2 Replies

4. Shell Programming and Scripting

for loop doesn't work

I have a script which uses below for loop: for (( i = 0 ; i <= 5; i++ )) do echo "Welcome $i times" done But when I run the script, it gives error message: Syntex Error : Bad for loop variable Can anyone guide to run it? Thanks in advance. (10 Replies)
Discussion started by: naw_deepak
10 Replies

5. Shell Programming and Scripting

alias doesn't work

Hi I have put alias ll='ls -la' in .profile file but it doesn't work. On hand it works it looks like the .profile file is not beeing read. How to check whitch file is loaded? ,profile? .bash_profile? My system: SunOS mion 5.10 Generic Shell: /bin/pfksh Thanks (2 Replies)
Discussion started by: miojamo
2 Replies

6. Shell Programming and Scripting

Function doesn't work

Hello, and here's my problem: I can't get my function to do what I want. When I call my function get_from_A_to_F I give it an argument $remainder. I want my function to substitute a number higher than 9 to a specific letter. If the argument is equal to 10 than it should change it to "A".... (8 Replies)
Discussion started by: linas
8 Replies

7. UNIX for Dummies Questions & Answers

Why doesn't this work?

find . -name "05_scripts" -type d -exec mv -f {}/'*.aep\ Logs' {}/.LogFiles \; Returns this failure: mv: rename ./019_0120_WS_WH_gate_insideTEST/05_scripts/*.aep\ Logs to ./019_0120_WS_WH_gate_insideTEST/05_scripts/.LogFiles/*.aep\ Logs: No such file or directory I don't know why it's trying... (4 Replies)
Discussion started by: scribling
4 Replies

8. Shell Programming and Scripting

-ne 0 doesn't work -le does

Hi, I am using korn shell. until ] do echo "\$# = " $# echo "$1" shift done To the above script, I passed 2 parameters and the program control doesn't enter inside "until" loop. If I change it to until ] then it does work. Why numeric comparison is not working with -ne and works... (3 Replies)
Discussion started by: ab_2010
3 Replies

9. Shell Programming and Scripting

Timeout doesn't work, please help me

#!/bin/sh trap "cleanup" TERM timeout=5 mainpid=$$ cleanup() { echo "at $i interupt" kill -9 0 } watchdog() { sleep $1 } (watchdog $timeout && kill -TERM $mainpid) & run_test() (10 Replies)
Discussion started by: yanglei_fage
10 Replies

10. Shell Programming and Scripting

Exit 1 doesn't work

Hi tail -f $PROGPATH/NBU_pgbaserestore_$1.log | while read LOGLINE do if ] && ! ] then date "+%d.%B.%Y %H:%M:%S" echo "ERROR: NBU" echo "$LOGLINE" TAILKILL=$(pgrep -P $$ -x tail) kill -9 $TAILKILL exit 1 ... (3 Replies)
Discussion started by: kvaikla
3 Replies
SHELL-QUOTE(1)						User Contributed Perl Documentation					    SHELL-QUOTE(1)

NAME
shell-quote - quote arguments for safe use, unmodified in a shell command SYNOPSIS
shell-quote [switch]... arg... DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands or files with embedded white space or shell globbing characters safely. Here are a few examples. EXAMPLES
ssh preserving args When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and passes them to "$SHELL -c". This doesn't work as intended: ssh host touch 'hi there' # fails It creates 2 files, hi and there. Instead, do this: cmd=`shell-quote touch 'hi there'` ssh host "$cmd" This gives you just 1 file, hi there. process find output It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote: eval set -- `find -type f -print0 | xargs -0 shell-quote --` debug shell scripts shell-quote is better than echo for debugging shell scripts. debug() { [ -z "$debug" ] || shell-quote "debug:" "$@" } With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can. save a command for later shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are things the user can't pass through), you can do something like this: user_switches= while [ $# != 0 ] do case x$1 in x--pass-through) [ $# -gt 1 ] || die "need an argument for $1" user_switches="$user_switches "`shell-quote -- "$2"` shift;; # process other switches esac shift done # later eval "shell-quote some-command $user_switches my args" OPTIONS
--debug Turn debugging on. --help Show the usage message and die. --version Show the version number and exit. AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions. AUTHOR
Roderick Schertler <roderick@argon.org> perl v5.16.3 2010-06-11 SHELL-QUOTE(1)
All times are GMT -4. The time now is 10:03 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy