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Top Forums Shell Programming and Scripting Delete a block of text delimited by blank lines when pattern is found Post 302151418 by gleu on Saturday 15th of December 2007 08:30:39 AM
Old 12-15-2007
Quote:
Originally Posted by radoulov
I think the OP wants something different:

...

$ sed -n '
/^$/ b block
H
$ b block
b
:block
x
/pattern/!p' data

block2
block2
block2
block2
[/code]
Yes. Thank you, Radoulov. You interpreted my question correctly. (Sorry, Franklin52 that it was none too clear).

I don't quite understand the above bit of code about the Set-Aside buffer (but I'll look it up later ...unless you or someone wants to explain for the benefit of others).

But, in any case, the final result with only lines of block2 is what I want. I will do a test run later ... before I use it in earnest on that 8 gig file at work. Thanks again.
 

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GREP(1) 						      General Commands Manual							   GREP(1)

NAME
grep - search a file for lines containing a given pattern SYNOPSIS
grep [-elnsv] pattern [file] ... OPTIONS
-e -e pattern is the same as pattern -c Print a count of lines matched -i Ignore case -l Print file names, no lines -n Print line numbers -s Status only, no printed output -v Select lines that do not match EXAMPLES
grep mouse file # Find lines in file containing mouse grep [0-9] file # Print lines containing a digit DESCRIPTION
Grep searches one or more files (by default, stdin) and selects out all the lines that match the pattern. All the regular expressions accepted by ed and mined are allowed. In addition, + can be used instead of * to mean 1 or more occurrences, ? can be used to mean 0 or 1 occurrences, and | can be used between two regular expressions to mean either one of them. Parentheses can be used for grouping. If a match is found, exit status 0 is returned. If no match is found, exit status 1 is returned. If an error is detected, exit status 2 is returned. SEE ALSO
cgrep(1), fgrep(1), sed(1), awk(9). GREP(1)
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