12-14-2007
grep string and find line before
hi,
i have to grep for string in file but i want to find the group of this line so i must get lines before and select the group.
the file look like :
####name_groupe1
alphanumeric line
alphanumeric line
..
####name_groupe2
alphanumeric line
alphanumeric line
..
####name_groupe3
alphanumeric line
alphanumeric line
..
al the file is like that :
i want to grep string if i find it in line i want to gret the name_group
i use :
grep -n "string to search" file | cut -f1 -d: to get the line number but i want to go lines before to find the group and store that in variable.
i use script shell.
thanks
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LOOK(1) BSD General Commands Manual LOOK(1)
NAME
look -- display lines beginning with a given string
SYNOPSIS
look [-df] [-t termchar] string [file]
DESCRIPTION
The look utility displays any lines in file which contain string as a prefix. As look performs a binary search, the lines in file must be
sorted.
If file is not specified, the file /usr/share/dict/words is used, only alphanumeric characters are compared and the case of alphabetic char-
acters is ignored.
Options:
-d Dictionary character set and order, i.e. only alphanumeric characters are compared.
-f Ignore the case of alphabetic characters.
-t Specify a string termination character, i.e. only the characters in string up to and including the first occurrence of termchar are
compared.
The look utility exits 0 if one or more lines were found and displayed, 1 if no lines were found, and >1 if an error occurred.
FILES
/usr/share/dict/words the dictionary
COMPATIBILITY
The original manual page stated that tabs and blank characters participated in comparisons when the -d option was specified. This was incor-
rect and the current man page matches the historic implementation.
SEE ALSO
grep(1), sort(1)
HISTORY
look appeared in Version 7 AT&T UNIX.
BSD
June 14, 1993 BSD