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UNIX for Dummies Questions & Answers
Count number of occurences of a word
Post 302148301 by $antaclau$ on Friday 30th of November 2007 07:22:34 PM
11-30-2007
Hi,
I am not much of an expert. But maybe we could something primitive like the following:
#!/bin/sh
#
# Usage: kountword "200" filename
#
srchWord="$1"
srchFilename="$2"
ctr=0
while read strLine
do
for eachWord in `echo $strLine`
do
if [ "$eachWord" = "$srchWord" ]
then
ctr=`expr $ctr + 1`
fi
done
done < srchFilename
printf "\n\ntheFile contains %s : %d times\n\n" $srchWord $ctr
#-----
I've not tried it but I beleive this should work
Thanks
$anta
I am not much of an expert. But maybe we could something primitive like the following:
#!/bin/sh
#
# Usage: kountword "200" filename
#
srchWord="$1"
srchFilename="$2"
ctr=0
while read strLine
do
for eachWord in `echo $strLine`
do
if [ "$eachWord" = "$srchWord" ]
then
ctr=`expr $ctr + 1`
fi
done
done < srchFilename
printf "\n\ntheFile contains %s : %d times\n\n" $srchWord $ctr
#-----
I've not tried it but I beleive this should work
Thanks
$anta
Last edited by $antaclau$; 11-30-2007 at 08:32 PM..
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