11-15-2007
Help with AWK and gsub
Hello,
I have a variable that displays the following results from a JVM....
1602100K->1578435K
I would like to collect the value of 1578435 which is the value after a garbage collection. I've tried the following command but it looks like I can't get the > to work. Any suggestions as to how to get the result?
jvmvalue=` echo $jvmvalue| awk '{gsub(/^[.->]+|[ K),]+$/,"");print}'`
Thanks for your time,
Nick
10 More Discussions You Might Find Interesting
1. Shell Programming and Scripting
Hi all,
This problem has cost me half a day, and i still do not know how to do.
Any help will be appreciated. Thanks advance.
I want to use a variable as the first parameters of gsub function of awk.
Example:
{
...
arri]=gsub(i,tolower(i),$1)
(which should be ambraced by //)
...
} (1 Reply)
Discussion started by: summer_cherry
1 Replies
2. Shell Programming and Scripting
Hi all
I want to do a simple substitution in awk but I am getting unexpected output. My function accepts a time and then prints out a validation message if the time is valid. However some times may include a : and i want to strip this out if it exists before i get to the validation. I have shown... (4 Replies)
Discussion started by: pxy2d1
4 Replies
3. Shell Programming and Scripting
Hi,
Can some one please explain the following line please throw some light on the ones marked in red
awk '{print $9}' ${FTP_LOG} | awk -v start=${START_DATE} 'BEGIN { FS = "." } { old_line1=$0; gsub(/\-/,""); if ( $3 >= start ) print old_line1 }' | awk -v end=${END_DATE} 'BEGIN { FS="." } {... (3 Replies)
Discussion started by: crosairs
3 Replies
4. Shell Programming and Scripting
I want to replace comma with space and "*646#" with space.
I am using the following code:
nawk -F"|" '{gsub(","," ",$3); gsub(/\*646\#/"," ",$3);print}' OFS="|" file
I am getting following error:
Help is appreciated (5 Replies)
Discussion started by: pinnacle
5 Replies
5. Shell Programming and Scripting
Being new to awk, I am still running into little stupid things. For this issues I am trying to search for all occurrences of a string in a file and replace all of those occurrences with a replacement string. I tried doing
awk '{gsub("|750101|", "|000000|", $0)}' infile > outfile
Unix... (3 Replies)
Discussion started by: jclanc8
3 Replies
6. Shell Programming and Scripting
Hey,
I would like to replace a string by a new one. Teh problem is that both strings should be variables to be flexible, because I am having a lot of files (with the same structure, but in different folders)
for i in daysim_*
do
cd $i/5/
folder=`pwd |awk '{print $1}'`
awk '{ if... (3 Replies)
Discussion started by: ergy1983
3 Replies
7. Shell Programming and Scripting
I want to transform a log file into input for a database.
Here's the log file:
Tue Aug 4 20:17:01 PDT 2009
Wireless users: 339
Daily Average: 48.4285
=
Tue Aug 11 20:17:01 PDT 2009
Wireless users: 295
Daily Average: 42.1428
=
Tue Aug 18 20:17:01 PDT 2009
Wireless users: 294
Daily... (6 Replies)
Discussion started by: Bubnoff
6 Replies
8. Shell Programming and Scripting
Hi, I want to print the first column with original value and without any double quotes
The output should look like
<original column>|<column without quotes>
$ cat a.txt
"20121023","19301229712","100397"
"20121023","19361629712","100778"
"20121030A","19361630412","100838"... (3 Replies)
Discussion started by: ysrini
3 Replies
9. UNIX for Dummies Questions & Answers
Hello,
I'm trying to substitute a string with leading zero for all the records except the trailer record using awk command and with variables. The input file test_med1.txt has data like below
1234ABC...........................9200............LF... (2 Replies)
Discussion started by: somu_june
2 Replies
10. Shell Programming and Scripting
Hello, I had some difficulty to understand the gsub function and maybe the regex in this script to remove all the punctuations:
awk 'gsub(//, " ", $0)' text.txtFile text.txt:
This is a test for gsub
I typed this random text file
which contains punctuation like ,.;!'"?/\ etc.
The script... (6 Replies)
Discussion started by: yifangt
6 Replies
LEARN ABOUT SUNOS
wbemconfig
wbemconfig(1M) System Administration Commands wbemconfig(1M)
NAME
wbemconfig - convert a JavaSpaces datastore to the newer Reliable Log datastore format
SYNOPSIS
/usr/sadm/lib/wbem/wbemconfig convert
DESCRIPTION
A Reliable Log directory is created that contains the converted data. This directory is named /var/sadm/wbem/logr.
The convert argument is the only supported option of this command. You should only run this command after stopping WBEM (CIM Object Man-
ager) with the init.wbem stop command. Otherwise your data may be corrupted.
This command successfully converts any proprietary custom MOFs you have created in the datastore, but not any CIM or Solaris MOFs you have
modified. These will be destroyed. To recompile any modified CIM or Solaris MOFs into the new datastore, run the mofcomp command on the MOF
files containing the class definitions.
Because the wbemconfig convert command invokes the JVM (Java Virtual Machine) to perform conversion of the JavaSpaces datastore, you must
be running the same version of the JVM as when the original JavaSpaces storage was created. After the wbemconfig convert command is com-
pleted, you can change to any version of the JVM you want.
To see what version of the JVM you are running, issue the java -version command.
OPTIONS
The following options are supported:
convert Convert a JavaSpaces datastore to the newer Reliable Log datastore format.
ATTRIBUTES
See attributes(5) for descriptions of the following attributes:
+-----------------------------+-----------------------------+
| ATTRIBUTE TYPE | ATTRIBUTE VALUE |
+-----------------------------+-----------------------------+
|Availability |SUNWwbcou |
+-----------------------------+-----------------------------+
SEE ALSO
init.wbem(1M), wbemadmin(1M), wbemlogviewer(1M), mofcomp(1M), attributes(5)
SunOS 5.10 24 Aug 2000 wbemconfig(1M)