11-15-2007
what is wrong with this script?
Hi,
I have this example script which gives error "[: ]: unexpected operator/operand". I need the '[]' brackets for operator precedence.
#!/bin/ksh
x="abc"
y="xyz"
z="123"
if [ "$x" = "abc" ] -a [ "$y" = "xyz" -o "$z" != "123" ]
then
print "yes"
else
print "no"
fi
Thanks
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LEARN ABOUT CENTOS
drop_operator
DROP
OPERATOR(7) PostgreSQL 9.2.7 Documentation DROP OPERATOR(7)
NAME
DROP_OPERATOR - remove an operator
SYNOPSIS
DROP OPERATOR [ IF EXISTS ] name ( { left_type | NONE } , { right_type | NONE } ) [ CASCADE | RESTRICT ]
DESCRIPTION
DROP OPERATOR drops an existing operator from the database system. To execute this command you must be the owner of the operator.
PARAMETERS
IF EXISTS
Do not throw an error if the operator does not exist. A notice is issued in this case.
name
The name (optionally schema-qualified) of an existing operator.
left_type
The data type of the operator's left operand; write NONE if the operator has no left operand.
right_type
The data type of the operator's right operand; write NONE if the operator has no right operand.
CASCADE
Automatically drop objects that depend on the operator.
RESTRICT
Refuse to drop the operator if any objects depend on it. This is the default.
EXAMPLES
Remove the power operator a^b for type integer:
DROP OPERATOR ^ (integer, integer);
Remove the left unary bitwise complement operator ~b for type bit:
DROP OPERATOR ~ (none, bit);
Remove the right unary factorial operator x! for type bigint:
DROP OPERATOR ! (bigint, none);
COMPATIBILITY
There is no DROP OPERATOR statement in the SQL standard.
SEE ALSO
CREATE OPERATOR (CREATE_OPERATOR(7)), ALTER OPERATOR (ALTER_OPERATOR(7))
PostgreSQL 9.2.7 2014-02-17 DROP OPERATOR(7)