I have a variable which consists of a string like this:
001 aaabc 44 a bbb12
How do I extract each substring, delimited by the spaces, into new variables - one for each substring?
eg var1 will be 001, var2 will be aaabc, var3 will be 44, var4 will be a, etc?
I've come up with this:... (2 Replies)
Hi all,
I have doubt can array in a shell script can store floating point numbers. i have tired. but i unable to work it out.
Please help me regarding this
Thank U
Naree (1 Reply)
im looping through an array setting three variables each time (one of the variables gives me the position in the array and is incremented each loop)
im trying to then set the variables to that position in the array without much luck. any ideas?
anArray=`$VAR1+$VAR2+"("$pos")"` (1 Reply)
Hi everyone, I am having some problems with my scripts so I hope you could help me.
I am trying to store the result of a division in a variable in tcshell but I have the problem that if:
For example, dividing 2/100 the result is 0.02 but if I store that I have "0".
How can I have 0.02... (8 Replies)
Guys anyone know how i can store fields into multiple variables in one go?
I'm wanting to grab the disk id's from format into disk1 and disk2
Below is what i want to work but i know it doesnt :-
: | format | awk '/^(\ +)/ {print $2}' | read disk1 disk2
The below does work...but i don't... (5 Replies)
I have a for loop that cycles twice and generates 1 random number for each pass through. I would like to be able to store the two numbers to use later for arithmetics. Is there a way to do that? Right now I can only seem to use the last random number for anything. Thanks. (4 Replies)
Hi Experts
I need your help to optimize my script to execute better as I have nearly 1M records & the script is taking close to 40 minutes to execute, so would need support on a faster alternative.
Input: file
{"house":"1024","zip":"2345","city":"asd","country":"zzv"}... (2 Replies)
Discussion started by: nk1984
2 Replies
LEARN ABOUT PHP
debug_zval_dump
DEBUG_ZVAL_DUMP(3) 1 DEBUG_ZVAL_DUMP(3)debug_zval_dump - Dumps a string representation of an internal zend value to outputSYNOPSIS
void debug_zval_dump (mixed $variable, [mixed $...])
DESCRIPTION
Dumps a string representation of an internal zend value to output.
PARAMETERS
o $variable
- The variable being evaluated.
RETURN VALUES
No value is returned.
EXAMPLES
Example #1
debug_zval_dump(3) example
<?php
$var1 = 'Hello World';
$var2 = '';
$var2 =& $var1;
debug_zval_dump(&$var1);
?>
The above example will output:
&string(11) "Hello World" refcount(3)
Note
Beware the refcount
The refcount value returned by this function is non-obvious in certain circumstances. For example, a developer might expect the
above example to indicate a refcount of 2. The third reference is created when actually calling debug_zval_dump(3).
This behavior is further compounded when a variable is not passed to debug_zval_dump(3) by reference. To illustrate, consider a
slightly modified version of the above example:
Example #2
<?php
$var1 = 'Hello World';
$var2 = '';
$var2 =& $var1;
debug_zval_dump($var1); // not passed by reference, this time
?>
The above example will output:
string(11) "Hello World" refcount(1)
Why refcount(1)? Because a copy of $var1 is being made, when the function is called.
This function becomes even more confusing when a variable with a refcount of 1 is passed (by copy/value):
Example #3
<?php
$var1 = 'Hello World';
debug_zval_dump($var1);
?>
The above example will output:
string(11) "Hello World" refcount(2)
A refcount of 2, here, is extremely non-obvious. Especially considering the above examples. So what's happening?
When a variable has a single reference (as did $var1 before it was used as an argument to debug_zval_dump(3)), PHP's engine opti-
mizes the manner in which it is passed to a function. Internally, PHP treats $var1 like a reference (in that the refcount is
increased for the scope of this function), with the caveat that if the passed reference happens to be written to, a copy is made,
but only at the moment of writing. This is known as "copy on write."
So, if debug_zval_dump(3) happened to write to its sole parameter (and it doesn't), then a copy would be made. Until then, the
parameter remains a reference, causing the refcount to be incremented to 2 for the scope of the function call.
SEE ALSO var_dump(3), debug_backtrace(3), References Explained, References Explained (by Derick Rethans).
PHP Documentation Group DEBUG_ZVAL_DUMP(3)