11-07-2007
reading from a file and pass as variables and ignore # in the file
file.txt contains
------------------
sat1 1300
#sat2 2400
sat3
sat4 500
sat5
I need to write a shell script that will output like the below
#output
sat1.ksh 1300
sat3.ksh
sat4.ksh 500
sat5.ksh
my try
-------
#!/bin/ksh
while read x y
do
echo "${x}.ksh ${y}"
done < file.txt
issues:
1) It doesnt ignore the 2nd line with # in the beginning.how to do it here.
2) Can we use awk or sed for the file reading? if yes then how?
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let(1) User Commands let(1)
NAME
let - shell built-in function to evaluate one or more arithmetic expressions
SYNOPSIS
ksh
let arg...
DESCRIPTION
ksh
Each arg is a separate "arithmetic expression" to be evaluated.
EXIT STATUS
The following exit values are returned:
0 The value of the last expression is non-zero.
1 The value of the last expression is zero.
ATTRIBUTES
See attributes(5) for descriptions of the following attributes:
+-----------------------------+-----------------------------+
| ATTRIBUTE TYPE | ATTRIBUTE VALUE |
+-----------------------------+-----------------------------+
|Availability |SUNWcsu |
+-----------------------------+-----------------------------+
SEE ALSO
ksh(1), set(1), typeset(1), attributes(5)
SunOS 5.10 15 Apr 1994 let(1)