Hello all,
Might be a silly question, on my AIX machine the year had changed to 2022 and some files were accessed on this date hence the time stamp on these files is with year 2022, there are many such files. i want to list all these file from the root dir and subdir with 2022 year... (3 Replies)
Hi there,
I'm using terminal on mac and using the ls -l command to list all the files in a directory. However, I only want to display the date and time stamp of each file rather than permissions, owner, group etc...
Is this possible?
Many thanks in advance
Dave (2 Replies)
I want a shell script which extract data from a log file which contains date and time-wise data and i need the data for a perticular interval of time...what can i do??? (3 Replies)
Hi,
I have a almost 4000 files in a perticular directory, but i want to ftp only todays files to some other unix server, not all the files.
could you please help me on this.
file formates are,
-rw-r--r-- 1 pipe pipe 341 Mar 9 12:35... (1 Reply)
hi everyone,
can someone suggest how i can list the contents of a directory and display their corresponding last modify time in the format yyyymmddhhmm?
thanks in advance! (16 Replies)
Hi all,
I am using the below script which display the files in the folder with the date range we specify. I want to add extra functionality that,
The listing files should be zipped using gzip. I tried to add exec gzip at the last line but it is not working.
Suggestions please.
... (2 Replies)
Hi,
I'm quite new to ksh scripting, can someone help me with this.
Requirements:
I need to create a script that list the files from a user input date range.
e. g. format of file:
*c1*log.2012-12-22-14-00*
*c1*log.2012-12-22-14-00*
*c1*log.2012-12-22-14-00*... (1 Reply)
Hi
there is a lot of file dated from last week till ofpresent date.
if i want to list only last 3 days files using ls command how can i do it
please suggest. below is the list of the file.
and i want to list files from MAy 12 to May 16.
Nov 22 2011 NSSM.UPPLSCPLB81
Jan 12... (2 Replies)
I have created this script
#!/bin/sh
FILES=/data/log/access_*.log
for f in $FILES
do
echo "Processing $f file"
cat $f | awk '{print $1}' | sort | uniq -c | sort -n | tail
done
It produces this output
Processing /data/log/access_abc.log file
114 1.1.1.1
167 2.2.2.2
... (38 Replies)