Hi ,
I am trying to increment the nested for loops parellely,but i cant ,i used continue 2 but the second loop not getting increment.
no1="1 6 5 4 8"
no2="4 7 8 0 1"
for var1 in $no1 ; do
for var2 in $no2 ; do
line1
line 2
line 3
continue 2
done
done
Please help on this (4 Replies)
I need to increment a date value through shell script.
Input value consist of start date and end date in DATE format of unix.
For eg.
I need increment a date value of 1/1/09 to 31/12/09 i.e for a whole yr.
The output must look like
1/1/09
2/2/09
.
.
.
31/1/09
.
.
1/2/09
.
28/2/09... (1 Reply)
Hi,
Iam new to scripting language.:o
can someone help me out solving this thread?hopingly ya....:)
I want to write a script which connects to db and searches the count in a table which has date column and id column.
If the count is not equal to 0 then it should increment the date with the one... (4 Replies)
Hi,
I have a variable lets say DATA_DATE.
I have to pass some value to this variable in YYYYMMDD format.
lets say today I have passed this variable as :
DATA_DATE=20100107
Then pls help me how to calculate another variable DATA_DATE1 (which is DATA_DATE+1).
The code should work... (3 Replies)
hi Friends,
Today_Dt=`date "+%Y-%m-%d"`
So the Today date is 2010-05-03
I have a file which has date values as below
2010-04-27
2010-04-02
2010-04-18
2010-04-28
2010-04-29
.. (1 Reply)
hi experts,
my requirement is like this i need to develop a shell script to update date part with new incremental date time in file some 'X' which is kept at some server location incrementing every two hours.as i am new to this scripting i need support from u people,thanx in advance (1 Reply)
Hello men.
How can i build a simple increment for $a by Xquery such as ?
let $a := 0
for $i in (1 to 10)
let $a := $a + 1
return $a
why a in this loop always is '1'
Thank you for reading, its will really helpful for my job if i can solve this problem :D:D (3 Replies)
Daily stupid question. I want to increment the file name everytime the script is run. So for example if the filename is manager.log and I run the script, I want the next sequence to be manager.log1. So to be clear I only want it to increment when the script is executed. So
./script... (10 Replies)
Hi,
I am using solaris 5.10 environment and need help on doing parallel increment of nested for loop.
Samples
#inside the code the values assigned to a variable by another awk command will be like
a=/xyz/pg/as
/xyz/pg/as2
/xyz/pg/as3
b=/xyz/sd/fd1
/xyz/sd/fd2
/xyz/sd/fd3
for q in... (1 Reply)
Discussion started by: ananan
1 Replies
LEARN ABOUT PHP
datetime.setdate
DATETIME.SETDATE(3) 1 DATETIME.SETDATE(3)DateTime::setDate - Sets the date
Object oriented style
SYNOPSIS
public DateTime DateTime::setDate (int $year, int $month, int $day)
DESCRIPTION
Procedural style
DateTime date_date_set (DateTime $object, int $year, int $month, int $day)
Resets the current date of the DateTime object to a different date.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $year
- Year of the date.
o $month
- Month of the date.
o $day
- Day of the date.
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
CHANGELOG
+--------+---------------------------------------------------+
|Version | |
| | |
| | Description |
| | |
+--------+---------------------------------------------------+
| 5.3.0 | |
| | |
| | Changed the return value on success from NULL to |
| | DateTime. |
| | |
+--------+---------------------------------------------------+
EXAMPLES
Example #1
DateTime.setDate(3) example
Object oriented style
<?php
$date = new DateTime();
$date->setDate(2001, 2, 3);
echo $date->format('Y-m-d');
?>
Procedural style
<?php
$date = date_create();
date_date_set($date, 2001, 2, 3);
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2001-02-03
Example #2
Values exceeding ranges are added to their parent values
<?php
$date = new DateTime();
$date->setDate(2001, 2, 28);
echo $date->format('Y-m-d') . "
";
$date->setDate(2001, 2, 29);
echo $date->format('Y-m-d') . "
";
$date->setDate(2001, 14, 3);
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2001-02-28
2001-03-01
2002-02-03
SEE ALSO DateTime.setISODate(3), DateTime.setTime(3).
PHP Documentation Group DATETIME.SETDATE(3)