I have been working on a script that executes on a number of different operating systems. As a result I was trying to set a variable or perhaps variable array depending on the OS. I tried the following using eval and such but so far have not had any luck. Is there a way to do something like the following.
I tried a host of different things, like putting eval into the variable and escaping the quotes but it just did not seem to work correctly. Any ideas, or am I better off writing the output of the command to a temp file and reading from the file?
Thanks in advance.
I like porter's idea of using a function, but if you wanted to do it like you've specified, you'd put it in backticks.
hi there,
In my shell script I'm using a variable $ICO to speicfy the type of file that I'm processing e.g. VFR = France.
further in my shell I'm trying to programatically set the sql file thtat I want to run :-
REPORTTXT=/tmp/$ICO3hr.dat
however when I check the value (as below) :-
... (4 Replies)
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set -a
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Hi i have two question
1. Yahoo!
In above there are total three words
1.1. www
1.2. yahoo
1.3 com
how can i take all three things in different variable, i dont understand that how to separate dot.
it looks like that
a=www
b=yahoo
c=com
2. i have variable xyz whois value... (7 Replies)
I want to instert Category:XXXXX into the 2. line
something like this should work, but I have somewhere the wrong sytanx. something with the linebreak goes wrong:
sed "2i\\${n}Category:$cat\n"
Sample:
Titel Blahh Blahh abllk sdhsd sjdhf
Blahh Blah Blahh
Blahh
Should look like... (2 Replies)
I know this script is crummy, but I was just messing around.. how do I get sed's insert command to allow variable expansion to show the filename?
#!/bin/bash
filename=`echo $0`
/usr/bin/sed '/#include/ {
i\
the filename is `$filename`
}' $1
exit 0 (8 Replies)
For example I have variable like below
echo $OUTPUT
/some/path/`uname -n`
when I try to use the variable OUTPUT like below
cd $OUTPUT or cd ${OUTPUT}
I am getting bad substituion error message
$ cd $OUTPUT
ksh: cd: bad substitution
$ cd ${OUTPUT}
ksh: cd: bad substitution
... (1 Reply)
Hi,
I am trying to do the following thing
var='date'
$var
Above command substitutes date for and in turn runs the date command and i am getting the todays date value.
I am trying to do the same thing as following, but facing some problems,
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Hello,
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Hello All,
Hope you're doing well !
I am trying below command to be passed in a shell script, header_date_14 is a variable and $1 is the name of a file I intend to pass as a command line argument, however command line argument is not being accepted.
header_date_14=$(m_dump... (8 Replies)