Numbers statrting with 0 are evaluated as octal numbers : 070820 is an invalid octal number.
A solution is to force decimal base evaluation :
This script will not give you any error, but i am not sure that the result is what you are expected.
Incrementng the date will give you invalid dates, for example :
070831+1=070832 <= Invalid date
Jean-Pierre.
Hi ,
I am trying to increment the nested for loops parellely,but i cant ,i used continue 2 but the second loop not getting increment.
no1="1 6 5 4 8"
no2="4 7 8 0 1"
for var1 in $no1 ; do
for var2 in $no2 ; do
line1
line 2
line 3
continue 2
done
done
Please help on this (4 Replies)
I need to increment a date value through shell script.
Input value consist of start date and end date in DATE format of unix.
For eg.
I need increment a date value of 1/1/09 to 31/12/09 i.e for a whole yr.
The output must look like
1/1/09
2/2/09
.
.
.
31/1/09
.
.
1/2/09
.
28/2/09... (1 Reply)
Hi,
Iam new to scripting language.:o
can someone help me out solving this thread?hopingly ya....:)
I want to write a script which connects to db and searches the count in a table which has date column and id column.
If the count is not equal to 0 then it should increment the date with the one... (4 Replies)
Hi,
I have a variable lets say DATA_DATE.
I have to pass some value to this variable in YYYYMMDD format.
lets say today I have passed this variable as :
DATA_DATE=20100107
Then pls help me how to calculate another variable DATA_DATE1 (which is DATA_DATE+1).
The code should work... (3 Replies)
hi Friends,
Today_Dt=`date "+%Y-%m-%d"`
So the Today date is 2010-05-03
I have a file which has date values as below
2010-04-27
2010-04-02
2010-04-18
2010-04-28
2010-04-29
.. (1 Reply)
hi experts,
my requirement is like this i need to develop a shell script to update date part with new incremental date time in file some 'X' which is kept at some server location incrementing every two hours.as i am new to this scripting i need support from u people,thanx in advance (1 Reply)
Hello men.
How can i build a simple increment for $a by Xquery such as ?
let $a := 0
for $i in (1 to 10)
let $a := $a + 1
return $a
why a in this loop always is '1'
Thank you for reading, its will really helpful for my job if i can solve this problem :D:D (3 Replies)
Daily stupid question. I want to increment the file name everytime the script is run. So for example if the filename is manager.log and I run the script, I want the next sequence to be manager.log1. So to be clear I only want it to increment when the script is executed. So
./script... (10 Replies)
Hi,
I am using solaris 5.10 environment and need help on doing parallel increment of nested for loop.
Samples
#inside the code the values assigned to a variable by another awk command will be like
a=/xyz/pg/as
/xyz/pg/as2
/xyz/pg/as3
b=/xyz/sd/fd1
/xyz/sd/fd2
/xyz/sd/fd3
for q in... (1 Reply)
Discussion started by: ananan
1 Replies
LEARN ABOUT PHP
datetimeinterface.format
DATETIMEINTERFACE.FORMAT(3) 1 DATETIMEINTERFACE.FORMAT(3)DateTime::format - Returns date formatted according to given format
Object oriented style
SYNOPSIS
public string DateTime::format (string $format)
DESCRIPTION
string DateTimeImmutable::format (string $format) string DateTimeInterface::format (string $format)
Procedural style
string date_format (DateTimeInterface $object, string $format)
Returns date formatted according to given format.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3)
o $format
- Format accepted by date(3).
RETURN VALUES
Returns the formatted date string on success or FALSE on failure.
EXAMPLES
Example #1
DateTimeInterface.format(3) example
Object oriented style
<?php
$date = new DateTime('2000-01-01');
echo $date->format('Y-m-d H:i:s');
?>
Procedural style
<?php
$date = date_create('2000-01-01');
echo date_format($date, 'Y-m-d H:i:s');
?>
The above example will output:
2000-01-01 00:00:00
NOTES
This method does not use locales. All output is in English.
SEE ALSO date(3).
PHP Documentation Group DATETIMEINTERFACE.FORMAT(3)