10-25-2007
Quote:
Originally Posted by
porter
Then the bit of memory that 'p' ends up pointing to has the contents 0x55.
If you have an uninitialised pointer it is just that, uninitialised, and will have the contents of whatever memory was at that point in the stack. As luck would have it, the &ch[0] did not trap and neither did accessing p.
Yes exactly as you had said.
And with this argument it is not guaranteed that the code would never crash.
To simulate that I could spawn this code between several process so that there could be an instance in the stack frame where there would be no value pointed to by ' p ' and ultimately crashing
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