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Full Discussion: size of char array in c
Top Forums Programming size of char array in c Post 302141948 by kahuna on Tuesday 23rd of October 2007 03:18:02 PM
Old 10-23-2007
Quote:
Originally Posted by phani_sree
how can i give the array size dynamically so that i can store the data from 1 to an infinte characters
Your expectations are unrealistic. No computer has an infinite amount of memory. The best you can do is allocate some finite space, process it, and then process the next portion of an infinite input.

Jim Mcnamara's code will allow you to declare arrays of variable size. I think you may be saying is that you don't know the amount of memory up front. If that is the case, you can allocate a reasonable amount of memory and try to reallocate (man realloc()) a larger chunk when you find you need more space.
 

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LEARN ABOUT LINUX

ustrzcpy

ustrzcpy(3alleg4)						  Allegro manual						 ustrzcpy(3alleg4)

NAME

       ustrzcpy - Copies a string into another one, specifying size. Allegro game programming library.

SYNOPSIS

       #include <allegro.h>

       char *ustrzcpy(char *dest, int size, const char *src);

DESCRIPTION

       This  function  copies `src' (including the terminating null character) into `dest', whose length in bytes is specified by `size' and which
       is guaranteed to be null-terminated even if `src' is bigger than `size'.

       Note that, even for empty strings, your destination string must have at least enough bytes to store the terminating null character  of  the
       string,	and  your  parameter `size' must reflect this. Otherwise, the debug version of Allegro will abort at an assertion, and the release
       version of Allegro will overrun the destination buffer.

RETURN VALUE

       Returns the value of `dest'.

SEE ALSO

       uconvert(3alleg4), ustrcpy(3alleg4), ustrzncpy(3alleg4), ex3buf(3alleg4), exgui(3alleg4)

Allegro 							   version 4.4.2						 ustrzcpy(3alleg4)
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