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Top Forums Programming Reason for Segmentation fault Post 302141789 by kahuna on Monday 22nd of October 2007 10:57:53 AM
Old 10-22-2007
Quote:
Originally Posted by royalibrahim
Code:
   char *ch; (or) ch = 'A';   // but if it assigned to any string then no segmentation fault

It's not clear what your actual code is. If you do not assign a value to the character pointer "ch", then it is pointing to an undefined location in memory and so it is not surprising that this would error. If you assign 'A' to ch, you are assigning the hex value of 'A' to the POINTER, which probably is not pointing to a valid memory location.
 

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