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Top Forums UNIX for Dummies Questions & Answers command to get count in unzipped folder Post 302141016 by arunkumar_mca on Wednesday 17th of October 2007 08:43:53 AM
Old 10-17-2007
command to get count in unzipped folder

Hi All,

Is there is a way to do this in a single unix command

I have unzipped some files into a directory ..

I want to check the count of the files in the directory and also i need to check whether the files is having read permision or not.. I know it can be done by a script isthere any way to it in a single command

Thanks,
Arun
 

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FILECAP:(8)						  System Administration Utilities					       FILECAP:(8)

NAME
filecap - a program to see capabilities SYNOPSIS
filecap [ -a | -d | /dir | /dir/file [cap1 cap2 ...] ] DESCRIPTION
filecap is a program that prints out a report of programs with file based capabilities. If a file is not in the report or there is no report at all, no capabilities were found. For expedience, the default is to check only the directories in the PATH environmental variable. If the -a command line option is given, then all directories will be checked. If a directory is passed, it will recursively check that directory. If a path to a file is given, it will only check that file. If the path to the file includes capabilities, then they are written to the file. OPTIONS
-a This tells the program to show all capabilities starting from the / directory. Normally the PATH environmental variable is used to show you capabilities on files you are likely to execute. -d This dumps all capabilities for reference. EXAMPLES
To check file capabilities in $PATH: filecap To check file capabilities of whole system: filecap -a To check file capabilities recursively in a directory: filecap /usr To check file capabilities of a specific program: filecap /bin/passwd To list all possible capabilities: filecap -d To set a file capability on a specific program: filecap /bin/ping net_raw net_admin SEE ALSO
pscap(8), netcap(8), capabilities(7). AUTHOR
Steve Grubb Red Hat March 2009 FILECAP:(8)
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