10-16-2007
10 More Discussions You Might Find Interesting
1. UNIX for Dummies Questions & Answers
does anybody know how to find out the number of
days elapsed between 2 dates
e.g.
days elapsed between 020212 and 020110 (YYMMDD format)
Thanking you in advance.
Ravi. (1 Reply)
Discussion started by: rkkiran
1 Replies
2. Shell Programming and Scripting
Hi All
How to get the difference between two dates in no of days ??? My date format is like this YYYY/MM/DD. I have to get the no of days between two dates in the given format.
I tried to search the forum but nothing came up similar to my requitement. Your help will be appreciated.
... (1 Reply)
Discussion started by: csaha
1 Replies
3. Shell Programming and Scripting
Hi All,
Can unix cshell list out the number of days between 070201 and 070205 (format is yymmdd) and list out all the dates in between in similiar format.
set startdate = `date '+%y%m%d'` #eg 070201
set enddate = `date '+%y%m%d'` #eg 070205
i would expect the number of days to be 5... (2 Replies)
Discussion started by: Raynon
2 Replies
4. Shell Programming and Scripting
Hello,
I would like to find out the number of days between two dates of the format yyyy-mm-dd.
Any help on this is highly appreciated.
Thanks. (6 Replies)
Discussion started by: Data469
6 Replies
5. Shell Programming and Scripting
Hi
I need one single command to get number of days between
two given dates.datecalc is not working.
ex.
fromdate:01.04.2010
todate :24.04.2010
i should get the out put as 23
Thanks in advance (4 Replies)
Discussion started by: suryanarayana
4 Replies
6. Shell Programming and Scripting
I have two times in the format of YYMMDD. Does anyone know an easy way in ksh for me to display how many days are between the two dates?
Example1:
X=101202
Y=101205
There are 3 days between X & Y
Example2:
X=101202
Y=111202
There are 365 days between X & Y
Example3:
X=101205... (3 Replies)
Discussion started by: oldman2
3 Replies
7. Web Development
Is this code good for this purpose?
<?php
$date1 = mktime(0,0,0,01,01,1991);
$date2 = mktime(0,0,0,03,22,2012);
$diff = $date2 - $date1;
$days = $diff / (60*60*24);
echo ($days . "<br />");
?> (3 Replies)
Discussion started by: kovacsakos
3 Replies
8. Shell Programming and Scripting
I wrote the day calculator also in bash. I would like to now, that is it good so?
#!/bin/bash
datum1=`date -d "1991/1/1" "+%s"`
datum2=`date "+%s"`
diff=$(($datum2-$datum1))
days=$(($diff/(60*60*24)))
echo $days
Thanks in advance for your help! (3 Replies)
Discussion started by: kovacsakos
3 Replies
9. UNIX for Advanced & Expert Users
Hi Am using Unix Ksh
I have a two date input as
DATE1=02/12/2012
DATE2=30/12/2012
I Need the output as only sunday date
02/12/2012
09/12/2012
16/12/2012
23/12/2012
30/12/2012
can anyone pls help me..
thanks in advance... (2 Replies)
Discussion started by: Venkatesh1
2 Replies
10. Shell Programming and Scripting
Gents.
Please can u help.
I would like to calculate the days between two dates.
Example file1 ( previous date)
file1 - Input file
9/29/2010 10195
9/29/2010 1057
2/2/2016 10
2/2/2016 10169
2/2/2016 1057
2/3/2016 10005
2/3/2016 10014
In file2 I add the actual date using this code.... (9 Replies)
Discussion started by: jiam912
9 Replies
LEARN ABOUT DEBIAN
lchage
lchage(8) System Manager's Manual lchage(8)
NAME
lchage - Display or change user password policy
SYNOPSIS
lchage [OPTION]... user
DESCRIPTION
Displays or allows changing password policy of user.
OPTIONS
-d, --date=days
Set the date of last password change to days after Jan 1 1970.
-E, --expire=days
Set the account expiration date to days after Jan 1 1970. Set days to -1 to disable account expiration.
-i, --interactive
Ask all questions when connecting to the user database, even if default answers are set up in libuser configuration.
-I, --inactive=days
Disable the account after days after password expires (after the user user is required to change the password).
-l, --list
Only list current user's policy and make no changes.
-m, --mindays=days
Require at least days days between password changes. Set days to 0 to disable this checking.
-M, --maxdays=days
Require changing the password after days since last password change. Set days to 99999 to disable this checking.
-W, --warndays=days
Start warning the user days before password expires (before the user is required to change the password).
EXIT STATUS
The exit status is 0 on success, nonzero on error.
libuser Jan 12 2005 lchage(8)