10-15-2007
Number of days between two distinct dates
Hi
I'm looking for a .ksh script/function that will calculate ONLY the number of days between two distinct dates. Further convert the number of days to weeks and display. I need this to be part of another larger script that checks the password expiry on several servers and notifies the administrator about ageing passwords.
Can someone please provide me with a plugin function/script that i could use for this purpose.
fyi, i reviewed the datecalc script but it does not serve my purpose entirely. Much obliged to anyone who can help...
Regards
Radheymohan
10 More Discussions You Might Find Interesting
1. UNIX for Dummies Questions & Answers
does anybody know how to find out the number of
days elapsed between 2 dates
e.g.
days elapsed between 020212 and 020110 (YYMMDD format)
Thanking you in advance.
Ravi. (1 Reply)
Discussion started by: rkkiran
1 Replies
2. Shell Programming and Scripting
Hi All
How to get the difference between two dates in no of days ??? My date format is like this YYYY/MM/DD. I have to get the no of days between two dates in the given format.
I tried to search the forum but nothing came up similar to my requitement. Your help will be appreciated.
... (1 Reply)
Discussion started by: csaha
1 Replies
3. Shell Programming and Scripting
Hi All,
Can unix cshell list out the number of days between 070201 and 070205 (format is yymmdd) and list out all the dates in between in similiar format.
set startdate = `date '+%y%m%d'` #eg 070201
set enddate = `date '+%y%m%d'` #eg 070205
i would expect the number of days to be 5... (2 Replies)
Discussion started by: Raynon
2 Replies
4. Shell Programming and Scripting
Hello,
I would like to find out the number of days between two dates of the format yyyy-mm-dd.
Any help on this is highly appreciated.
Thanks. (6 Replies)
Discussion started by: Data469
6 Replies
5. Shell Programming and Scripting
Hi
I need one single command to get number of days between
two given dates.datecalc is not working.
ex.
fromdate:01.04.2010
todate :24.04.2010
i should get the out put as 23
Thanks in advance (4 Replies)
Discussion started by: suryanarayana
4 Replies
6. Shell Programming and Scripting
I have two times in the format of YYMMDD. Does anyone know an easy way in ksh for me to display how many days are between the two dates?
Example1:
X=101202
Y=101205
There are 3 days between X & Y
Example2:
X=101202
Y=111202
There are 365 days between X & Y
Example3:
X=101205... (3 Replies)
Discussion started by: oldman2
3 Replies
7. Web Development
Is this code good for this purpose?
<?php
$date1 = mktime(0,0,0,01,01,1991);
$date2 = mktime(0,0,0,03,22,2012);
$diff = $date2 - $date1;
$days = $diff / (60*60*24);
echo ($days . "<br />");
?> (3 Replies)
Discussion started by: kovacsakos
3 Replies
8. Shell Programming and Scripting
I wrote the day calculator also in bash. I would like to now, that is it good so?
#!/bin/bash
datum1=`date -d "1991/1/1" "+%s"`
datum2=`date "+%s"`
diff=$(($datum2-$datum1))
days=$(($diff/(60*60*24)))
echo $days
Thanks in advance for your help! (3 Replies)
Discussion started by: kovacsakos
3 Replies
9. UNIX for Advanced & Expert Users
Hi Am using Unix Ksh
I have a two date input as
DATE1=02/12/2012
DATE2=30/12/2012
I Need the output as only sunday date
02/12/2012
09/12/2012
16/12/2012
23/12/2012
30/12/2012
can anyone pls help me..
thanks in advance... (2 Replies)
Discussion started by: Venkatesh1
2 Replies
10. Shell Programming and Scripting
Gents.
Please can u help.
I would like to calculate the days between two dates.
Example file1 ( previous date)
file1 - Input file
9/29/2010 10195
9/29/2010 1057
2/2/2016 10
2/2/2016 10169
2/2/2016 1057
2/3/2016 10005
2/3/2016 10014
In file2 I add the actual date using this code.... (9 Replies)
Discussion started by: jiam912
9 Replies
LEARN ABOUT REDHAT
shadow
SHADOW(5) File Formats Manual SHADOW(5)
NAME
shadow - encrypted password file
DESCRIPTION
shadow contains the encrypted password information for user's accounts and optional the password aging information. Included is
Login name
Encrypted password
Days since Jan 1, 1970 that password was last changed
Days before password may be changed
Days after which password must be changed
Days before password is to expire that user is warned
Days after password expires that account is disabled
Days since Jan 1, 1970 that account is disabled
A reserved field
The password field must be filled. The encryped password consists of 13 to 24 characters from the 64 character alphabet a thru z, A thru
Z, 0 thru 9, . and /. Refer to crypt(3) for details on how this string is interpreted.
The date of the last password change is given as the number of days since Jan 1, 1970. The password may not be changed again until the
proper number of days have passed, and must be changed after the maximum number of days. If the minimum number of days required is greater
than the maximum number of day allowed, this password may not be changed by the user.
An account is considered to be inactive and is disabled if the password is not changed within the specified number of days after the pass-
word expires. An account will also be disabled on the specified day regardless of other password expiration information.
This information supercedes any password or password age information present in /etc/passwd.
This file must not be readable by regular users if password security is to be maintained.
FILES
/etc/passwd - user account information
/etc/shadow - encrypted user passwords
SEE ALSO
chage(1), login(1), passwd(1), su(1), passwd(5), pwconv(8), pwunconv(8), sulogin(8)
AUTHOR
Julianne Frances Haugh (jockgrrl@ix.netcom.com)
SHADOW(5)