Hello, i have a script which checks if the user entered 8 numeric characters in the form of YYYYMMDD (birth date). If the user entered any non numeric characters, an error will be displayed:
Code:
# Check to see if the 8 characters are all numbers
# If not show error essage
# And prompt user for more input
echo $char | grep -q '^[0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9]$'
if [ $? -ne 0 ]
then
echo "You have entered non-numeric values. Please type in the form of YYYYMMDD"
read char
continue
Is there a simpler way to write this command without using the [0-9] value for each field? Any help would be appreciated
Okay, well this is more or less my first attempt at writing a shell script.
Anyways, here's my code:
cd ${PATH}
if
then
rm ${FILE}
./anotherScript
else
exit 1
fi
exit 1
Anyways, it's a pretty simple script that is supposed to search for the... (4 Replies)
Hi,
I want to use grep inside a test statement, but I am getting an error message.
Two variables
testvarNum=5
testvarNonNum=x
echo $testvarNum | grep *
The result of this is as follows:
5
However, when I try the following (i.e. to test if the variable is numeric or non-numeric):... (3 Replies)
Hello ...again.
I am stuck on this part, I have a loop with processes an operations file.
and calls different functions depending on what is in loop, which processes a database file...
#so far my add function works as intended
add()
{
...blah blah;
}
# delete is kinda working... (13 Replies)
Hi Team,
-rwxr-xr-x 1 kmani00 system 9 Nov 08 03:29 tempfile.txt
-rwxrwxrwx 1 kmani00 devgrp 0 Nov 08 03:32 testfile.txt
by exec the following command, i did not get any output.
> test -s tempfile.txt
> a=`test -s tempfile.txt`
> echo $a
>
by exec the... (4 Replies)
Hello all,
working on Solaris 10 in ksh.
Basicly, in my function, i'm trying to test that all my unix cmd's are true (exit status 0) else you flag the rcControlRule to 1 without going into spagetti mode code testing every $? in a if statement.
The mdb is probably a little tricky cause it... (3 Replies)
I have a list of files like below, Do we have grep command to find files?
If i grep 03874 it should display the file 3874, Grep command should ignore 0 at the beginning. There could be more many leading 0's in filename.
$ ls -ltr
total 5
-rw-r--r-- 1 mqm mqm 15 Feb 19 17:07 4769... (3 Replies)
I want to xheck if a file exists that uses wildcards as only the partial filename is known using the test Command, and when it exists then output just the number of lines in the file... do not include the filename. Then this output, is it captured by the CommandOutput or the ReturnValue as I want... (2 Replies)
As an exercise, I'm trying to re-write this code without the compound square brackets, using grep and test. Need to know what to do about the "equal-tilde".
#!/bin/bash
# test-integer2: evaluate the value of an integer.
INT=-5
if +$ ]]; then
if ; then
echo "INT is zero."
else
if ; then... (17 Replies)
Discussion started by: Xubuntu56
17 Replies
LEARN ABOUT PHP
dateinterval.format
DATEINTERVAL.FORMAT(3) 1 DATEINTERVAL.FORMAT(3)DateInterval::format - Formats the interval
SYNOPSIS
public string DateInterval::format (string $format)
DESCRIPTION
Formats the interval.
PARAMETERS
o $format
-
The following characters are recognized in the $format parameter string. Each format character must be prefixed by a percent sign (
%).
+------------------+--------------------------------------+---+
|$format character | | |
| | | |
| | Description | |
| | | |
| | Example values | |
| | | |
+------------------+--------------------------------------+---+
| | | |
| % | | |
| | | |
| | Literal % | |
| | | |
| | | |
| | % | |
| | | |
| | | |
| Y | | |
| | | |
| | Years, numeric, at least 2 digits | |
| | with leading 0 | |
| | | |
| | | |
| | 01, 03 | |
| | | |
| | | |
| y | | |
| | | |
| | Years, numeric | |
| | | |
| | | |
| | 1, 3 | |
| | | |
| | | |
| M | | |
| | | |
| | Months, numeric, at least 2 digits | |
| | with leading 0 | |
| | | |
| | | |
| | 01, 03, 12 | |
| | | |
| | | |
| m | | |
| | | |
| | Months, numeric | |
| | | |
| | | |
| | 1, 3, 12 | |
| | | |
| | | |
| D | | |
| | | |
| | Days, numeric, at least 2 digits | |
| | with leading 0 | |
| | | |
| | | |
| | 01, 03, 31 | |
| | | |
| | | |
| d | | |
| | | |
| | Days, numeric | |
| | | |
| | | |
| | 1, 3, 31 | |
| | | |
| | | |
| a | | |
| | | |
| | Total number of days as a result of | |
| | a DateTime::diff or (unknown) other- | |
| | wise | |
| | | |
| | | |
| | 4, 18, 8123 | |
| | | |
| | | |
| H | | |
| | | |
| | Hours, numeric, at least 2 digits | |
| | with leading 0 | |
| | | |
| | | |
| | 01, 03, 23 | |
| | | |
| | | |
| h | | |
| | | |
| | Hours, numeric | |
| | | |
| | | |
| | 1, 3, 23 | |
| | | |
| | | |
| I | | |
| | | |
| | Minutes, numeric, at least 2 digits | |
| | with leading 0 | |
| | | |
| | | |
| | 01, 03, 59 | |
| | | |
| | | |
| i | | |
| | | |
| | Minutes, numeric | |
| | | |
| | | |
| | 1, 3, 59 | |
| | | |
| | | |
| S | | |
| | | |
| | Seconds, numeric, at least 2 digits | |
| | with leading 0 | |
| | | |
| | | |
| | 01, 03, 57 | |
| | | |
| | | |
| s | | |
| | | |
| | Seconds, numeric | |
| | | |
| | | |
| | 1, 3, 57 | |
| | | |
| | | |
| R | | |
| | | |
| | Sign " -" when negative, " +" when | |
| | positive | |
| | | |
| | | |
| | -, + | |
| | | |
| | | |
| r | | |
| | | |
| | Sign " -" when negative, empty when | |
| | positive | |
| | | |
| | | |
| | -, | |
| | | |
+------------------+--------------------------------------+---+
RETURN VALUES
Returns the formatted interval.
NOTES
Note
The DateInterval::format method does not recalculate carry over points in time strings nor in date segments. This is expected
because it is not possible to overflow values like "32 days" which could be interpreted as anything from "1 month and 4 days" to "1
month and 1 day".
EXAMPLES
Example #1
DateInterval example
<?php
$interval = new DateInterval('P2Y4DT6H8M');
echo $interval->format('%d days');
?>
The above example will output:
4 days
Example #2
DateInterval and carry over points
<?php
$interval = new DateInterval('P32D');
echo $interval->format('%d days');
?>
The above example will output:
32 days
Example #3
DateInterval and DateTime::diff with the %a and %d modifiers
<?php
$january = new DateTime('2010-01-01');
$february = new DateTime('2010-02-01');
$interval = $february->diff($january);
// %a will output the total number of days.
echo $interval->format('%a total days')."
";
// While %d will only output the number of days not already covered by the
// month.
echo $interval->format('%m month, %d days');
?>
The above example will output:
31 total days
1 month, 0 days
SEE ALSO
DateTime::diff.
PHP Documentation Group DATEINTERVAL.FORMAT(3)