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Top Forums Shell Programming and Scripting Returning filename and matching lines Post 302139355 by atripat on Friday 5th of October 2007 02:49:42 PM
Old 10-05-2007
Here is one quick and simple way:

Code:
for file in `grep -l aabbcc *`
        do
        echo $file
        grep -n aabbcc $file | sed 's/:/ /'
        done

Replace aabbcc in the code above with the pattern you are looking for in the file.
Replace the first * in the code with your file name pattern.
sed will only look for the first instance of : on the output from grep.
 

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ZGREP(1)						    BSD General Commands Manual 						  ZGREP(1)

NAME
zgrep, zegrep, zfgrep -- print lines matching a pattern in gzip-compressed files SYNOPSIS
zgrep [grep-flags] [--] pattern [files ...] zegrep [grep-flags] [--] pattern [file ...] zfgrep [grep-flags] [--] pattern [file ...] DESCRIPTION
zgrep runs grep(1) on files or stdin, if no files argument is given, after decompressing them with zcat(1). The grep-flags and pattern arguments are passed on to grep(1). If an -e flag is found in the grep-flags, zgrep will not look for a pattern argument. zegrep calls egrep(1), while zfgrep calls fgrep(1). EXIT STATUS
In case of missing arguments or missing pattern, 1 will be returned, otherwise 0. SEE ALSO
egrep(1), fgrep(1), grep(1), gzip(1), zcat(1) AUTHORS
Thomas Klausner <wiz@NetBSD.org> BSD
December 28, 2003 BSD
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