10-05-2007
How to delete more lines
Hi experts !
I need to delete two range of lines in this command. Is that possible ?
ie. line 1 - 22 and 36 to 40. How do i do this in one go ??
ls -1t ${RESULT}/*.trc | while read TRACE_FILE
do
grep CONTROLFILE ${TRACE_FILE}
rc=$?
if [[ $rc -eq 0 ]]
then
sed -e '
1,22d
s/'${ORACLE_SID}'/'${TARGET}'/g
/\# Recovery/,/ARCHIVE LOG ALL;/d
s/REUSE DATABASE/SET DATABASE/
s/NORESETLOGS ARCHIVELOG/RESETLOGS NOARCHIVELOG/
s/ALTER DATABASE OPEN/ALTER DATABASE OPEN RESETLOGS/
' ${TRACE_FILE} > ${OUT_CTL}
break
fi
done
Thanks in advance
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GREP(1) General Commands Manual GREP(1)
NAME
grep - search a file for lines containing a given pattern
SYNOPSIS
grep [-elnsv] pattern [file] ...
OPTIONS
-e -e pattern is the same as pattern
-c Print a count of lines matched
-i Ignore case
-l Print file names, no lines
-n Print line numbers
-s Status only, no printed output
-v Select lines that do not match
EXAMPLES
grep mouse file # Find lines in file containing mouse
grep [0-9] file # Print lines containing a digit
DESCRIPTION
Grep searches one or more files (by default, stdin) and selects out all the lines that match the pattern. All the regular expressions
accepted by ed and mined are allowed. In addition, + can be used instead of * to mean 1 or more occurrences, ? can be used to mean 0 or 1
occurrences, and | can be used between two regular expressions to mean either one of them. Parentheses can be used for grouping. If a
match is found, exit status 0 is returned. If no match is found, exit status 1 is returned. If an error is detected, exit status 2 is
returned.
SEE ALSO
cgrep(1), fgrep(1), sed(1), awk(9).
GREP(1)