10-04-2007
how to exclude the GREP command from GREP
I am doing "ps -f" to see my process.
but I get lines that one of it represents the ps command itself.
I want to grep it out using -v flag, but than I get another process that belongs to the GREP itself :
I would like to exclude
[root@localhost ~]# ps -f
UID PID PPID C STIME TTY TIME CMD
root 15794 15792 0 13:48 pts/2 00:00:00 -bash
root 16157 15794 0 14:01 pts/2 00:00:00 ps -f
[root@localhost ~]# ps -f | grep -v ps
UID PID PPID C STIME TTY TIME CMD
root 15794 15792 0 13:48 pts/2 00:00:00 -bash
root 16160 15794 0 14:02 pts/2 00:00:00 -bash
while all I want is to get my pid line only.
or maybe you know another command that returns my pid and ppid only ?
thanks
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PS(1) General Commands Manual PS(1)
NAME
ps - process status
SYNOPSIS
ps [-alxU] [kernel mm fs]
OPTIONS
-a Print all processes with controlling terminals
-l Give long listing
-x Include processes without a terminal
EXAMPLES
ps -axl # Print all processes and tasks in long format
DESCRIPTION
Ps prints the status of active processes. Normally only the caller's own processes are listed in short format (the PID, TTY, TIME and CMD
fields as explained below). The long listing contains:
F Kernel flags: 001: free slot 002: no memory map 004: sending; 010: receiving 020:
inform on pending signals 040: pending signals 100: being traced.
S State: R: runnable W: waiting (on a message) S: sleeping (i.e.,suspended on MM or FS) Z:
zombie T: stopped
UID, PID, PPID, PGRP The user, process, parent process and process group ID's.
SZ Size of the process in kilobytes.
RECV Process/task on which a receiving process is waiting or sleeping.
TTY Controlling tty for the process.
TIME Process' cumulative (user + system) execution time.
CMD Command line arguments of the process.
The files /dev/{mem,kmem} are used to read the system tables and command line arguments from. Terminal names in /dev are used to generate
the mnemonic names in the TTY column, so ps is independent of terminal naming conventions.
PS(1)