1. With zsh you don't need to call find
(note that "**" globs multiple "/", it's a recursive globbing)
all that you need is:
or, in this case, even just:
2. You can execute it first with ls -l,
just to be sure that it generates the files you need to remove:
If there are many files and you get the "argument list too long" error,
use this:
----------------------------------------------------------------------
Since in future, we will be migrating to Unix Box, so then in that case, this command will work perfectly fine...right?
I want to write a sh script that will find files older than 2 hours and tar them. I've had a look at the find man page but can't see how to do it by hours.
Help please.
Thanx (1 Reply)
I need to write a program that will only remove those files that are older than 2 hours.
Is there some variation of
find . -mtime ? -name '*'
that I can use?
Thanks as always for your help.
Regards,
Dave :) (2 Replies)
What is the command to remove files that are generated 6 hours or older? The find and remove tells only how to remove if the file is one day old or more. Appreciate quick reply. Thanks (3 Replies)
Every day a new .zip file is uploaded to a folder and at mid-night the zip file is to be extracted into a /data/ folder, inside a date-named folder.
# This should extract the contents of a zip file into the /data/ folder into a date based folder
/usr/bin/unzip -a -o... (15 Replies)
I need a script to find files older than 8 hours...
I know i can use mmin but the same is not working...the same only support mtime...
This is the script i created..but the same is only giving 1 hour old..as I have given dt_H as 1 only...but if i give 8..it can go in -(negative)..how to get the... (5 Replies)
Hi all
I have directory /tmp and i have logs are written in it every 18 to 20 hours in date format.
now i need write some if condition which can find which files came into /tmp dir with name start from LOG_`date`.log in last 24 hours.
can somebody help me on this. (2 Replies)
Hi All,
I am using the below script to find all the files in a folder which are older than 6 hours and delete all those files, but some how I am not getting the required output.
find $HOME/Log -type f -name "*.log" -amin +360 -exec rm *.* {} \
can any one please check and let me know... (13 Replies)
How to Deleting Files Older than 1 hours.
Base on SunOS.
this file gen every 1 min.
-rw-r--r-- 1 nobody nobody 4960 Jan 27 02:02 23_201301270201.log
-rw-r--r-- 1 nobody amudu 2325 Jan 27 02:03 33_201301270202.log
-rw-r--r-- 1 nobody amudu 3255 Jan 27 02:03... (2 Replies)
Discussion started by: ooilinlove
2 Replies
LEARN ABOUT REDHAT
pam_xauth
pam_xauth(8) System Administrator's Manual pam_xauth(8)NAME
pam_xauth - forward xauth keys between users
SYNOPSIS
session optional /lib/security/pam_xauth.so arguments
DESCRIPTION
pam_xauth.so is designed to forward xauth keys (sometimes referred to as "cookies") between users.
Without pam_xauth, when xauth is enabled and a user uses the su command to assume another user's priviledges, that user is no longer able
to access the original user's X display because the new user does not have the key needed to access the display. pam_xauth solves the
problem by forwarding the key from the user running su (the source user) to the user whose identity the source user is assuming (the target
user) when the session is created, and destroying the key when the session is torn down.
This means, for example, that when you run su from an xterm sesssion, you will be able to run X programs without explicitly dealing with
the xauth command or ~/.Xauthority files.
pam_xauth will only forward keys if xauth can list a key connected to the $DISPLAY environment variable.
Primitive access control is provided by ~/.xauth/export in the invoking user's home directory and ~/.xauth/import in the target user's home
directory.
If a user has a ~/.xauth/import file, the user will only receive cookies from users listed in the file. If there is no ~/.xauth/import
file, the user will accept cookies from any other user.
If a user has a .xauth/export file, the user will only forward cookies to users listed in the file. If there is no ~/.xauth/export file,
and the invoking user is not root, the user will forward cookies to any other user. If there is no ~/.xauth/export file, and the invoking
user is root, the user will not forward cookies to other users.
Both the import and export files support wildcards (such as *). Both the import and export files can be empty, signifying that no users
are allowed.
ARGUMENTS
debug Turns on debugging messages sent to syslog.
xauthpath=/usr/X11R6/bin/xauth
Specify the path the xauth program (the default is /usr/X11R6/bin/xauth).
IMPLEMENTATION DETAILS
pam_xauth will work only if it is used from a setuid application in which the getuid() call returns the id of the user running the applica-
tion, and for which PAM can supply the name of the account that the user is attempting to assume. The typical application of this type is
su. The application must call both pam_open_session() and pam_close_session() with the ruid set to the uid of the calling user and the
euid set to root, and must have provided as the PAM_USER item the name of the target user.
pam_xauth calls xauth as the source user to extract the key for $DISPLAY, then calls xauth as the target user to merge the key into the a
temporary database and later remove the database.
pam_xauth cannot be told not to remove the keys when the session is closed.
SEE ALSO
/usr/share/doc/pam*/html/index.html
FILES
~/.xauth/import ~/.xauth/export
BUGS
Let's hope not, but if you find any, please report them via the "Bug Track" link at http://bugzilla.redhat.com/bugzilla/
AUTHOR
Nalin Dahyabhai <nalin@redhat.com>, based on original version by Michael K. Johnson <johnsonm@redhat.com>
Red Hat Linux 2001/9/27 pam_xauth(8)