I am creating a script that will look through a log file and print the previous days entries. However I do not want the complete line of the entry.
A single line of the log file is as follows:
Aug 3006:35:08 trnwvltfit1 /usr/lib/snmp/snmpdx: [ID 702911 daemon.error] Agent snmpd appeared dead but responded to ping
I am using the date of the line to determine which lines to print. However, I am only trying to print the parts of the line that are NOT highlighted in red. I have no knowledge of how long the line may be. How can this be done? So far I have:
I am sorry to repost this question. it was not clear, and I had the meeting and didn't response the question on time. I do really need help and appreciate your help very much.
I'm looking for a simple shell script that will read lots of audit log file (*.aud) in a log fold every 10 minutes,... (1 Reply)
I'm looking for a command or simple script that will read lots of audit log file (*.aud) in log fold every 10 minutes, and will output to one file based on sysdate - 10 minutes. assume the script is run at 11:12:20, and it
should grep the line from Wed Jun 17 11:02:43 2009 to end of file. after... (4 Replies)
Hi
this is my SQL script
$ wc -l insert_into_customers.sql
85601 insert_into_customers.sqlI wish to cut this file into 9 files each 10000 lines (the last one less)
$ wc -l insert_into_customers_00*.sql
10000 insert_into_customers_001.sql
10000 insert_into_customers_002.sql
... (1 Reply)
Hi,
I have a folder with multiple (< 33) .log files.
And I have to copy the lines between two patterns from all the .log files to a new file.
(script file with a loop?)
Thanks in advance.
1.log
...
..
xx1> begin
...
..
..
>>> Total: 2 Alarms
..
.. (17 Replies)
Hello,
Activity to perform:
1. Find all of the "*.tmp" files in a given user directory
2. Determine which ones have "find" in them.
3. Replace the "find sequence" of commands with a "list set" of commands.
Example:
Original file:
--------------
define lastn1 = "A"
define... (7 Replies)
RHEL 5.8
In a directory I have more than 200 files with the extension .log
Using head command I want to print first 20 lines of each log file.
For each .log file, it should print like below
Printing first 20 lines of : GRP_error_April29.log
Apr 29 04:02:05 raptor03b syslogd 1.4.1:... (4 Replies)
Hi everyone,
I have two files, namely:
file1:
file1Col1Row1;file1Col2Row1;file1Col3Row1
file1Col1Row2;file1Col2Row2;file1Col3Row2
file1Col1Row3;file1Col2Row3;file1Col3Row3file2:
file2Col1Row1;file2Col2Row1;file2Col3Row1
file2Col1Row2;file2Col2Row2;file2Col3Row2... (0 Replies)
I use "MineOS" (a linux distro with python scripts and web ui included for managing a Minecraft Server). The author of the scripts is currently having a problem with the Minecraft server log file being spammed with certain entries. He's working on clearing up the spam.
But in the meantime, I'm... (8 Replies)
Oracle Linux 6.4
In a directory I have more than 300 files with the extension .log
I want the first 5 and last 5 lines of these .log files to be printed on screen with each file's name.
Expected output :
Printing first 5 and last 5 lines of FX_WT_Feb8_2014.log
!! Authentication... (7 Replies)