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Full Discussion: Question about working with data to create new column
Top Forums Shell Programming and Scripting Question about working with data to create new column Post 302133050 by scottzx7rr on Tuesday 21st of August 2007 06:33:25 PM
Old 08-21-2007
vgersh99,

Thanks for the swift reply. I appreciate your assistance. I hate being very rusty and trying to relearn something. LOL Question would that work also for doing a multiple series of math? Meaning I have a column that I want to do math upon. I am taking the column and multiplying it by 0.125, then that total will be subtracted by 1, then that total will be multiplied by 0.0225 for the final total.

((Column*0.125)-1)*0.0225=new column

Meaning would I be able to do something like this:

BEGIN {
FS=OFS=","
}

{
format="%0" length($2) "d"
$(NF+1)=sprintf(format, ((($4*0.125)-1)*0.0225))
print
}
 

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LEARN ABOUT PHP

db2_field_type

DB2_FIELD_TYPE(3)							 1							 DB2_FIELD_TYPE(3)

db2_field_type - Returns the data type of the indicated column in a result set

SYNOPSIS

       string db2_field_type (resource	$stmt, mixed  $column)

DESCRIPTION

	Returns the data type of the indicated column in a result set.

PARAMETERS

	      o $stmt
		- Specifies a statement resource containing a result set.

	      o $column
		-  Specifies  the  column in the result set. This can either be an integer representing the 0-indexed position of the column, or a
		string containing the name of the column.

RETURN VALUES

	Returns a string containing the defined data type of the specified column. If the specified column does  not  exist  in  the  result  set,
       db2_field_type(3) returns FALSE.

SEE ALSO

       db2_field_display_size(3), db2_field_name(3), db2_field_num(3), db2_field_precision(3), db2_field_scale(3), db2_field_width(3).

PHP Documentation Group 													 DB2_FIELD_TYPE(3)
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