some math problems in C Post: 302132686

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Top Forums Programming some math problems in C Post 302132686 by cdfd123 on Sunday 19th of August 2007 12:30:18 AM

08-19-2007

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some math problems in C

I want to calculate secant method using C language
That is a program---->
#include<stdio.h>
#include<math.h>
#include<stdlib.h>
main()
{
double fx(double x);
double x0,x1,x2,f0,f1,f2,err;
int n,i;
printf("\n\n f(x) =x*x*x-5*x-7");
printf("\n\nEnter an interval [x0,x1] in"
" which root is to be found");
printf("\nx0 =");
scanf("%f",&x0); /* INTERVAL[x0,x1] is to be entered here */
printf("x1=");
scanf("%f",&x1);
printf("\n Enter the number of iterations=");
scanf("%d",&n);
printf("\npress any key for display of iterations...\n");
getchar();
i=0;
while (n > 0)
{
f0=fx(x0);
f1=fx(x1);
x2 = x1-((x1-x0)/(f1-f0))*f1;
i++;
printf("\n x[%d]=%f x[%d]=%f",i,i-1,x0,i,x1);
printf("\n f[%d]=%f f[%d]=%f",i,i-1,f0,i,f1);
printf("\n x[%d]=%f",i+1,x2);
x0=x1;
x1=x2;
getchar();
}
printf("\n\nThe value of root is =%f",x2);
}
double fx(double x)
{
double f;
f=x*x*x-5*x-7;
return(f);
}

But while running not the erreo is displayed but the results displayed is
f(x) =x*x*x-5*x-7

Enter an interval [x0,x1] in which root is to be found
x0 =2.5
x1=3

Enter the number of iterations=4

press any key for display of iterations...

x[1]=0.000000 x[0]=0.000000
f[1]=-7.000000 f[0]=-7.000000
x[2]=inf

Means not able to calculate root as seen in the output it is x[1]=0...

so what will be the problem????

cdfd123

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printf

PRINTF(1)								FSF								 PRINTF(1)

NAME

       printf - format and print data

SYNOPSIS

       printf FORMAT [ARGUMENT]...
       printf OPTION

DESCRIPTION

       NOTE:  your shell may have its own version of printf which will supercede the version described here. Please refer to your shell's documen-
       tation for details about the options it supports.

       Print ARGUMENT(s) according to FORMAT.

       --help display this help and exit

       --version
	      output version information and exit

       FORMAT controls the output as in C printf.  Interpreted sequences are:

       "     double quote

       NNN  character with octal value NNN (0 to 3 digits)

       \     backslash

       a     alert (BEL)

            backspace

       c     produce no further output

       f     form feed

       
     new line

       
     carriage return

       	     horizontal tab

       v     vertical tab

       xNNN  byte with hexadecimal value NNN (1 to 3 digits)

       uNNNN character with hexadecimal value NNNN (4 digits)

       UNNNNNNNN
	      character with hexadecimal value NNNNNNNN (8 digits)

       %%     a single %

       %b     ARGUMENT as a string with `' escapes interpreted

       and all C format specifications ending with one of diouxXfeEgGcs, with ARGUMENTs converted to proper type first.  Variable widths are  han-
       dled.

AUTHOR

       Written by David MacKenzie.

REPORTING BUGS

       Report bugs to <bug-coreutils@gnu.org>.

COPYRIGHT

       Copyright (C) 2002 Free Software Foundation, Inc.
       This is free software; see the source for copying conditions.  There is NO warranty; not even for MERCHANTABILITY or FITNESS FOR A PARTICU-
       LAR PURPOSE.

SEE ALSO

       The full documentation for printf is maintained as a Texinfo manual.  If the info and printf programs are properly installed at your  site,
       the command

	      info printf

       should give you access to the complete manual.

GNU coreutils 4.5.3						   February 2003							 PRINTF(1)