some math problems in C Post: 302132686

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Top Forums Programming some math problems in C Post 302132686 by cdfd123 on Sunday 19th of August 2007 12:30:18 AM

08-19-2007

Registered User

some math problems in C

I want to calculate secant method using C language
That is a program---->
#include<stdio.h>
#include<math.h>
#include<stdlib.h>
main()
{
double fx(double x);
double x0,x1,x2,f0,f1,f2,err;
int n,i;
printf("\n\n f(x) =x*x*x-5*x-7");
printf("\n\nEnter an interval [x0,x1] in"
" which root is to be found");
printf("\nx0 =");
scanf("%f",&x0); /* INTERVAL[x0,x1] is to be entered here */
printf("x1=");
scanf("%f",&x1);
printf("\n Enter the number of iterations=");
scanf("%d",&n);
printf("\npress any key for display of iterations...\n");
getchar();
i=0;
while (n > 0)
{
f0=fx(x0);
f1=fx(x1);
x2 = x1-((x1-x0)/(f1-f0))*f1;
i++;
printf("\n x[%d]=%f x[%d]=%f",i,i-1,x0,i,x1);
printf("\n f[%d]=%f f[%d]=%f",i,i-1,f0,i,f1);
printf("\n x[%d]=%f",i+1,x2);
x0=x1;
x1=x2;
getchar();
}
printf("\n\nThe value of root is =%f",x2);
}
double fx(double x)
{
double f;
f=x*x*x-5*x-7;
return(f);
}

But while running not the erreo is displayed but the results displayed is
f(x) =x*x*x-5*x-7

Enter an interval [x0,x1] in which root is to be found
x0 =2.5
x1=3

Enter the number of iterations=4

press any key for display of iterations...

x[1]=0.000000 x[0]=0.000000
f[1]=-7.000000 f[0]=-7.000000
x[2]=inf

Means not able to calculate root as seen in the output it is x[1]=0...

so what will be the problem????

cdfd123

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LEARN ABOUT X11R4

catan

CATAN(3)						     Linux Programmer's Manual							  CATAN(3)

NAME

       catan, catanf, catanl - complex arc tangents

SYNOPSIS

       #include <complex.h>

       double complex catan(double complex z);
       float complex catanf(float complex z);
       long double complex catanl(long double complex z);

       Link with -lm.

DESCRIPTION

       These  functions  calculate the complex arc tangent of z.  If y = catan(z), then z = ctan(y).  The real part of y is chosen in the interval
       [-pi/2,pi/2].

       One has:

	   catan(z) = (clog(1 + i * z) - clog(1 - i * z)) / (2 * i)

VERSIONS

       These functions first appeared in glibc in version 2.1.

ATTRIBUTES

       For an explanation of the terms used in this section, see attributes(7).

       +----------------------------+---------------+---------+
       |Interface		    | Attribute     | Value   |
       +----------------------------+---------------+---------+
       |catan(), catanf(), catanl() | Thread safety | MT-Safe |
       +----------------------------+---------------+---------+
CONFORMING TO

       C99, POSIX.1-2001, POSIX.1-2008.

EXAMPLE

       /* Link with "-lm" */

       #include <complex.h>
       #include <stdlib.h>
       #include <unistd.h>
       #include <stdio.h>

       int
       main(int argc, char *argv[])
       {
	   double complex z, c, f;
	   double complex i = I;

	   if (argc != 3) {
	       fprintf(stderr, "Usage: %s <real> <imag>
", argv[0]);
	       exit(EXIT_FAILURE);
	   }

	   z = atof(argv[1]) + atof(argv[2]) * I;

	   c = catan(z);
	   printf("catan() = %6.3f %6.3f*i
", creal(c), cimag(c));

	   f = (clog(1 + i * z) - clog(1 - i * z)) / (2 * i);
	   printf("formula = %6.3f %6.3f*i
", creal(f2), cimag(f2));

	   exit(EXIT_SUCCESS);
       }

SEE ALSO

       ccos(3), clog(3), ctan(3), complex(7)

COLOPHON

       This page is part of release 4.15 of the Linux man-pages project.  A description of the project, information about reporting bugs, and  the
       latest version of this page, can be found at https://www.kernel.org/doc/man-pages/.

								    2015-04-19								  CATAN(3)