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Top Forums Shell Programming and Scripting Count the number of occurence of perticular word from file Post 302130939 by Shell_Life on Wednesday 8th of August 2007 11:09:15 AM
Old 08-08-2007
Quote:
Originally Posted by cfajohnson

Code:
tr -cs 'A-Za-z' '\n' < FILE | grep -c "WORD"

This solution does not work.

Here is a sample file:
Code:
a aa aaa
aaa aa a
aaa aa a aaa aa a aaa

Here is one test:
Code:
tr -cs 'A-Za-z' '\n' < FILE | grep -c "aaa"

It gives the total of words as '3', when the answer is '5'.

Here is another possible solution for those who want to use shell script:
Code:
#!/bin/ksh
typeset -i mCnt=0
mWord='aaa'
for mEach in `cat input_file`
do
  if [ "${mEach}" = "${mWord}" ]; then
    mCnt=${mCnt}+1
  fi
done
echo 'Total words for '${mWord}' = '${mCnt}


Last edited by Shell_Life; 08-08-2007 at 12:14 PM..
 

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