|
|
Sponsored Content
Top Forums
Shell Programming and Scripting
how to add ' using awk
Post 302130484 by icemantj on Monday 6th of August 2007 10:58:05 AM
08-06-2007
|
|
10 More Discussions You Might Find Interesting
1. Shell Programming and Scripting
hi everybody:
My question is how could i add a new columns to a file that it has one column like this:
06/06/2005
06/07/2005
06/08/2005
06/09/2005
06/10/2005
06/11/2005
06/12/2005
06/13/2005
06/14/2005
06/15/2005
06/16/2005
06/17/2005
....
And i want add columns like :
06/06/2005 ... (4 Replies)
Discussion started by: tonet
4 Replies
2. Shell Programming and Scripting
I have a file like this:
running:running since Mon Mar 3 09:46:19 2008:
running:running since Thu Mar 6 22:36:51 2008:
running:running since Tue Dec 4 00:34:15 2007:
running:running since Tue Dec 4 00:34:16 2007:
running:running since Mon Jan 21 11:15:04 2008:
running:running since... (3 Replies)
Discussion started by: rbulus
3 Replies
3. Shell Programming and Scripting
Hey,
Im trying to format the last command to tell me just the user names, logins, and the time that they were logged in. So far I got the users logins using a loop that counts the amount of times a user logged in but im not sure how to start the time array. The time im trying to use is the last... (2 Replies)
Discussion started by: Trilogie
2 Replies
4. UNIX for Dummies Questions & Answers
Srr for being pain her
let say i have a data in a file like this
1@1000
2@2000
4@4000
5@7770
6@8998
7@80008
i am a newbie in Unix
i need to add a comma to integer using AWK function. for example, 1,000 or 80,008
how can i do that
ps. i'm using bash shell (1 Reply)
Discussion started by: Nutter
1 Replies
5. Shell Programming and Scripting
echo "0.1 2.0 0.4 2.0 4.3 1.0 6.0 9.0" | awk 'BEGIN {total=0} {total += $1} END {print total}'
I want to add the above output from the echo command, but i can't figure this out. The output above always spits out inaccurate numbers.
can someone please provide me with a one liner similar to... (4 Replies)
Discussion started by: SkySmart
4 Replies
6. Shell Programming and Scripting
I have the following awk one-liners:
awk '{if ($2==1) print 1, $1}' infile | awk '{sum+=$2}END{print 1, sum/NR}' > infile2
:
:
awk '{if ($2==n) print 1, $1}' infile | awk '{sum+=$2}END{print n, sum/NR}' > infile2
How to add a loop for instance from n=1 to n=100 in order to compact... (9 Replies)
Discussion started by: jarowit
9 Replies
7. Shell Programming and Scripting
Hello,
There was a nice article here located on this forum, but I have not posted enough to add that URL.
That touched up on how to do this, but I still have not been able to figure it out. The thread is closed.
I have a file that looks like:
02/16/2011,15:23,0:00:06,4455,8883332222... (5 Replies)
Discussion started by: truecall
5 Replies
8. Shell Programming and Scripting
Hi experts
I have lots of test.sh, each test.sh has the dotest1() function, I want to add below code before dotest1() if the runtest.sh don't contains "getopts", can someone show me the way
while getopts "s" arg
do
case $arg in
s)
echo "ss"
... (2 Replies)
Discussion started by: yanglei_fage
2 Replies
9. UNIX for Dummies Questions & Answers
Hi all. Wondering if someone can help with an awk solution to a problem I'm stumped with.
I have a matrix file with >1000 fields and would like to add another column after each column with a text label. For example:
Input:
$cat file.txt
name col1 col2 col3 coln
aaaa ... (2 Replies)
Discussion started by: torchij
2 Replies
10. Shell Programming and Scripting
I am trying to use awk to add a space in a string of text. My awk is close but does not produce the desured output. Thank you :).
input
washington aveLansing, MI
washington streetLansing, MI
Desired output
washington ave Lansing, MI
washington street Lansing, MI
awk -F"\t"... (9 Replies)
Discussion started by: cmccabe
9 Replies
LEARN ABOUT SUNOS
reject
accept(1M) System Administration Commands accept(1M) NAME
accept, reject - accept or reject print requests SYNOPSIS
accept destination... reject [-r reason] destination... DESCRIPTION
accept allows the queueing of print requests for the named destinations. reject prevents queueing of print requests for the named destinations. Use lpstat -a to check if destinations are accepting or rejecting print requests. accept and reject must be run on the print server; they have no meaning to a client system. OPTIONS
The following options are supported for reject: -r reason Assigns a reason for rejection of print requests for destination. Enclose reason in quotes if it contains blanks. reason is reported by lpstat -a. By default, reason is unknown reason for existing destinations, and new printer for destinations added to the system but not yet accepting requests. OPERANDS
The following operands are supported. destination The name of the destination accepting or rejecting print requests. Destination specifies the name of a printer or class of printers (see lpadmin(1M)). Specify destination using atomic name. See printers.conf(4) for information regarding the naming conventions for atomic names. EXIT STATUS
The following exit values are returned: 0 Successful completion. non-zero An error occurred. FILES
/var/spool/lp/* LP print queue. ATTRIBUTES
See attributes(5) for descriptions of the following attributes: +-----------------------------+-----------------------------+ | ATTRIBUTE TYPE | ATTRIBUTE VALUE | +-----------------------------+-----------------------------+ |Availability |SUNWpcu | +-----------------------------+-----------------------------+ |CSI |Enabled (see NOTES) | +-----------------------------+-----------------------------+ SEE ALSO
enable(1), lp(1), lpstat(1), lpadmin(1M), lpsched(1M), printers.conf(4), attributes(5) NOTES
accept and reject affect only queueing on the print server's spooling system. Requests made from a client system remain queued in the client system's queueing mechanism until they are cancelled or accepted by the print server's spooling system. accept is CSI-enabled except for the destination name. SunOS 5.10 8 Feb 1999 accept(1M)