hi everybody:
My question is how could i add a new columns to a file that it has one column like this:
06/06/2005
06/07/2005
06/08/2005
06/09/2005
06/10/2005
06/11/2005
06/12/2005
06/13/2005
06/14/2005
06/15/2005
06/16/2005
06/17/2005
....
And i want add columns like :
06/06/2005 ... (4 Replies)
I have a file like this:
running:running since Mon Mar 3 09:46:19 2008:
running:running since Thu Mar 6 22:36:51 2008:
running:running since Tue Dec 4 00:34:15 2007:
running:running since Tue Dec 4 00:34:16 2007:
running:running since Mon Jan 21 11:15:04 2008:
running:running since... (3 Replies)
Hey,
Im trying to format the last command to tell me just the user names, logins, and the time that they were logged in. So far I got the users logins using a loop that counts the amount of times a user logged in but im not sure how to start the time array. The time im trying to use is the last... (2 Replies)
Srr for being pain her
let say i have a data in a file like this
1@1000
2@2000
4@4000
5@7770
6@8998
7@80008
i am a newbie in Unix
i need to add a comma to integer using AWK function. for example, 1,000 or 80,008
how can i do that
ps. i'm using bash shell (1 Reply)
echo "0.1 2.0 0.4 2.0 4.3 1.0 6.0 9.0" | awk 'BEGIN {total=0} {total += $1} END {print total}'
I want to add the above output from the echo command, but i can't figure this out. The output above always spits out inaccurate numbers.
can someone please provide me with a one liner similar to... (4 Replies)
I have the following awk one-liners:
awk '{if ($2==1) print 1, $1}' infile | awk '{sum+=$2}END{print 1, sum/NR}' > infile2
:
:
awk '{if ($2==n) print 1, $1}' infile | awk '{sum+=$2}END{print n, sum/NR}' > infile2
How to add a loop for instance from n=1 to n=100 in order to compact... (9 Replies)
Hello,
There was a nice article here located on this forum, but I have not posted enough to add that URL.
That touched up on how to do this, but I still have not been able to figure it out. The thread is closed.
I have a file that looks like:
02/16/2011,15:23,0:00:06,4455,8883332222... (5 Replies)
Hi experts
I have lots of test.sh, each test.sh has the dotest1() function, I want to add below code before dotest1() if the runtest.sh don't contains "getopts", can someone show me the way
while getopts "s" arg
do
case $arg in
s)
echo "ss"
... (2 Replies)
Hi all. Wondering if someone can help with an awk solution to a problem I'm stumped with.
I have a matrix file with >1000 fields and would like to add another column after each column with a text label. For example:
Input:
$cat file.txt
name col1 col2 col3 coln
aaaa ... (2 Replies)
I am trying to use awk to add a space in a string of text. My awk is close but does not produce the desured output. Thank you :).
input
washington aveLansing, MI
washington streetLansing, MI
Desired output
washington ave Lansing, MI
washington street Lansing, MI
awk -F"\t"... (9 Replies)
Discussion started by: cmccabe
9 Replies
LEARN ABOUT DEBIAN
devel::refcount
Devel::Refcount(3pm) User Contributed Perl Documentation Devel::Refcount(3pm)NAME
"Devel::Refcount" - obtain the REFCNT value of a referent
SYNOPSIS
use Devel::Refcount qw( refcount );
my $anon = [];
print "Anon ARRAY $anon has " . refcount($anon) . " reference
";
my $otherref = $anon;
print "Anon ARRAY $anon now has " . refcount($anon) . " references
";
DESCRIPTION
This module provides a single function which obtains the reference count of the object being pointed to by the passed reference value.
FUNCTIONS
$count = refcount($ref)
Returns the reference count of the object being pointed to by $ref.
COMPARISON WITH SvREFCNT
This function differs from "Devel::Peek::SvREFCNT" in that SvREFCNT() gives the reference count of the SV object itself that it is passed,
whereas refcount() gives the count of the object being pointed to. This allows it to give the count of any referent (i.e. ARRAY, HASH,
CODE, GLOB and Regexp types) as well.
Consider the following example program:
use Devel::Peek qw( SvREFCNT );
use Devel::Refcount qw( refcount );
sub printcount
{
my $name = shift;
printf "%30s has SvREFCNT=%d, refcount=%d
",
$name, SvREFCNT($_[0]), refcount($_[0]);
}
my $var = [];
printcount 'Initially, $var', $var;
my $othervar = $var;
printcount 'Before CODE ref, $var', $var;
printcount '$othervar', $othervar;
my $code = sub { undef $var };
printcount 'After CODE ref, $var', $var;
printcount '$othervar', $othervar;
This produces the output
Initially, $var has SvREFCNT=1, refcount=1
Before CODE ref, $var has SvREFCNT=1, refcount=2
$othervar has SvREFCNT=1, refcount=2
After CODE ref, $var has SvREFCNT=2, refcount=2
$othervar has SvREFCNT=1, refcount=2
Here, we see that SvREFCNT() counts the number of references to the SV object passed in as the scalar value - the $var or $othervar
respectively, whereas refcount() counts the number of reference values that point to the referent object - the anonymous ARRAY in this
case.
Before the CODE reference is constructed, both $var and $othervar have SvREFCNT() of 1, as they exist only in the current lexical pad. The
anonymous ARRAY has a refcount() of 2, because both $var and $othervar store a reference to it.
After the CODE reference is constructed, the $var variable now has an SvREFCNT() of 2, because it also appears in the lexical pad for the
new anonymous CODE block.
PURE-PERL FALLBACK
An XS implementation of this function is provided, and is used by default. If the XS library cannot be loaded, a fallback implementation in
pure perl using the "B" module is used instead. This will behave identically, but is much slower.
Rate pp xs
pp 225985/s -- -66%
xs 669570/s 196% --
SEE ALSO
o Test::Refcount - assert reference counts on objects
AUTHOR
Paul Evans <leonerd@leonerd.org.uk>
perl v5.14.2 2011-11-15 Devel::Refcount(3pm)