date in awk Post: 302130426

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need date in awk

Hello all: Running SunOS 5.6 on a SPARCstation-5...and using bourne shell. This is a line from a script I am writing: LOG=/opt/msplib/sys/logs/alarm.log$* grep "Call Answered" $LOG |wc -l | awk '{ print "Call Answered\t" $1 "\tIVR\t" "AR-a"} It works great, and produces the...

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Hello All, in my script i want to get the month part of date. I need the month part because i will grep logs every month using it. When i run the "date" command i got the below result: serverprod{root}>date Mon Aug 24 14:01:20 EEST 2009 but when i type the below command i got Aug24...

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using awk to print date

i want to use awk to print the first,second and add date as third column in a file awk -F"|" ' { print $1,$2,current date }' tom.unl >> top.txt how can i achieve this,i need the comma's to seperate them and finally print current date and time as the third. i want output like...

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Hi, I want to print the number of lines of a file along with filename and today's date. Ex: XXX|07-22-2010|8 I am using as wc -c -l file.txt | awk '{print "XXX|",date +"%m-%d-%Y","|",$1}' But this one prints as AAA| 0 | 8 Can anyone please help me on this for printing the date? ...

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Hi All.... I need to pass date into awk and parse logfile based on that.... i used both awk and /usr/xpg4/bin/awk... both are throwing up error..... So here is the stuff... when i use /usr/xpg4/bin/awk : DATE=`date '+%Y %b %d'` START=00 END=23 /usr/xpg4/bin/awk -v DATE={"$DATE"} -v...

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Find week of the year for given date using date command inside awk

Hi all, Need an urgent help on the below scenario. script: awk -F"," 'BEGIN { #some variable assignment} { #some calculation and put values in array} END { year=#getting it from array and assume this will be 2014 month=#getting it from array and this will be 05 date=#...

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awk command in hp UNIX subtract 30 days automatically from current date without date illegal option

current date command runs well awk -v t="$(date +%Y-%m-%d)" -F "'" '$1 < t' myname.dat subtract 30 days fails awk -v t="$(date --date="-30days" +%Y-%m-%d)" -F "'" '$1 < t' myname.dat awk command in hp unix subtract 30 days automatically from current date without date illegal option error...

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awk IF date comparison help

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LEARN ABOUT MINIX

paste

PASTE(1)						      General Commands Manual							  PASTE(1)

NAME

       paste - paste multiple files together

SYNOPSIS

       paste [-s] [-d list] file...

OPTIONS

       -d     Set delimiter used to separate columns to list.

       -s     Print files sequentially, file k on line k.

EXAMPLES

       paste file1 file2   # Print file1 in col 1, file2 in col 2

       paste -s f1 f2	   # Print f1 on line 1 and f2 on line 2

       paste -d : file1 file2
			   # Print the lines separated by a colon

DESCRIPTION

       Paste  concatenates  corresponding  lines of the given input files and writes them to standard output. The lines of the different files are
       separated by the delimiters given with the option -s. If no list is given, a tab is substituted for every linefeed, except  the	last  one.
       If  end-of-file	is hit on an input file, subsequent lines are empty.  Suppose a set of k files each has one word per line.  Then the paste
       output will have k columns, with the contents of file j in column j.  If the -s flag is given, then the first file is on line 1, the second
       file on line 2, etc.  In effect, -s turns the output sideways.

       If  a list of delimiters is given, they are used in turn.  The C escape sequences 
, 	, \, and  are used for linefeed, tab, backslash,
       and the null string, respectively.

																	  PASTE(1)

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

need date in awk

Discussion started by: cdunavent

2. UNIX for Dummies Questions & Answers

Use of system date in awk

Discussion started by: Manish4

3. UNIX for Dummies Questions & Answers

awk for date

Discussion started by: EAGL�

4. Shell Programming and Scripting

using awk to print date

Discussion started by: tomjones