07-31-2007
grep a log file to filter previous dates
Hi,
I have problem of filtering a log file from my perl script.
#cat /data/pinpe.csv_20070731 | nawk -v FS=, '{print $1','$18','$22','$26}' | grep -w 100 | grep -w 1 | nawk '{print $4}'
Below is the output:
2009-06-16
2009-01-29
2009-06-02
2008-03-05
2007-08-05
2007-09-24
2007-07-10
2007-10-27
2007-10-14
2008-08-02
2007-11-10
2007-10-16
2008-09-15
2008-01-30
2008-12-08
2007-09-26
2007-11-29
2008-04-01
2007-11-21
2007-12-18
2007-10-04
2007-06-29
2008-01-13
2007-10-28
2007-10-20
2007-09-13
2008-11-05
2008-08-05
2008-04-10
2007-09-10
2008-10-12
2007-11-29
2008-04-02
2009-03-05
2009-07-18
2007-11-16
2007-10-13
Now my dilemma is I want to filter this ouput by my preferred dates. I wanted it to output the date from yesterday and backwards. In other words I want to filter all the dates less than today's date (i.e. 2007-07-30, 2007-07-29, 2007-07-28, etc. and below). And finally count the number of lines for the final output.
Tnx in advance.
Br, Pete
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ZGREP(1) General Commands Manual ZGREP(1)
NAME
zgrep - search possibly compressed files for a regular expression
SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename...
DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code:
(-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the
standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep.
If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.
EXIT CODE
2 - An option that is not supported was specified.
AUTHOR
Charles Levert (charles@comm.polymtl.ca)
SEE ALSO
grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)
ZGREP(1)