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Top Forums Shell Programming and Scripting Korn Shell Script - Getting yesterdays date Post 302129437 by lorcan on Tuesday 31st of July 2007 12:54:47 AM
Old 07-31-2007
Quote:
Originally Posted by frustrated1
I need to get yesterdays date in the format yyyymmdd
I can get today's date simply enough - 20031112

Is there any way to substract 1 from this easily enough in korn shell script?

It has to be korn shell and not perl
To get the todays date
Code:
echo $(date "+%G%m%d")

Yesterday date
Code:
echo $(date -d "1 day ago" "+%G%m%d")

 

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DATETIME.SETDATE(3)							 1						       DATETIME.SETDATE(3)

DateTime::setDate - Sets the date

       Object oriented style

SYNOPSIS
public DateTime DateTime::setDate (int $year, int $month, int $day) DESCRIPTION
Procedural style DateTime date_date_set (DateTime $object, int $year, int $month, int $day) Resets the current date of the DateTime object to a different date. PARAMETERS
o $object -Procedural style only: A DateTime object returned by date_create(3). The function modifies this object. o $year - Year of the date. o $month - Month of the date. o $day - Day of the date. RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure. CHANGELOG
+--------+---------------------------------------------------+ |Version | | | | | | | Description | | | | +--------+---------------------------------------------------+ | 5.3.0 | | | | | | | Changed the return value on success from NULL to | | | DateTime. | | | | +--------+---------------------------------------------------+ EXAMPLES
Example #1 DateTime.setDate(3) example Object oriented style <?php $date = new DateTime(); $date->setDate(2001, 2, 3); echo $date->format('Y-m-d'); ?> Procedural style <?php $date = date_create(); date_date_set($date, 2001, 2, 3); echo date_format($date, 'Y-m-d'); ?> The above examples will output: 2001-02-03 Example #2 Values exceeding ranges are added to their parent values <?php $date = new DateTime(); $date->setDate(2001, 2, 28); echo $date->format('Y-m-d') . " "; $date->setDate(2001, 2, 29); echo $date->format('Y-m-d') . " "; $date->setDate(2001, 14, 3); echo $date->format('Y-m-d') . " "; ?> The above example will output: 2001-02-28 2001-03-01 2002-02-03 SEE ALSO
DateTime.setISODate(3), DateTime.setTime(3). PHP Documentation Group DATETIME.SETDATE(3)
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