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Top Forums UNIX for Dummies Questions & Answers how to execute a while loop for 20 minutes? Post 302125284 by Perderabo on Thursday 5th of July 2007 01:06:26 AM
Old 07-05-2007
I would try something like
Code:
#! /usr/bin/ksh
secs=$(perl -e 'print time(), "\n"')
((targetsecs=secs+20*60))
while ((secs < targetsecs)) ; do
        sleep 5
        echo running
        secs=$(perl -e 'print time(), "\n"')
done
echo done
exit 0

 

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Mail::SpamAssassin::Timeout(3)				User Contributed Perl Documentation			    Mail::SpamAssassin::Timeout(3)

NAME
Mail::SpamAssassin::Timeout - safe, reliable timeouts in perl SYNOPSIS
# non-timeout code... my $t = Mail::SpamAssassin::Timeout->new({ secs => 5, deadline => $when }); $t->run(sub { # code to run with a 5-second timeout... }); if ($t->timed_out()) { # do something... } # more non-timeout code... DESCRIPTION
This module provides a safe, reliable and clean API to provide alarm(2)-based timeouts for perl code. Note that $SIG{ALRM} is used to provide the timeout, so this will not interrupt out-of-control regular expression matches. Nested timeouts are supported. PUBLIC METHODS
my $t = Mail::SpamAssassin::Timeout->new({ ... options ... }); Constructor. Options include: secs => $seconds time interval, in seconds. Optional; if neither "secs" nor "deadline" is specified, no timeouts will be applied. deadline => $unix_timestamp Unix timestamp (seconds since epoch) when a timeout is reached in the latest. Optional; if neither secs nor deadline is specified, no timeouts will be applied. If both are specified, the shorter interval of the two prevails. $t->run($coderef) Run a code reference within the currently-defined timeout. The timeout is as defined by the secs and deadline parameters to the constructor. Returns whatever the subroutine returns, or "undef" on timeout. If the timer times out, "$t-<gt"timed_out()> will return 1. Time elapsed is not cumulative; multiple runs of "run" will restart the timeout from scratch. On the other hand, nested timers do observe outer timeouts if they are shorter, resignalling a timeout to the level which established them, i.e. code running under an inner timer can not exceed the time limit established by an outer timer. When restarting an outer timer on return, elapsed time of a running code is taken into account. $t->run_and_catch($coderef) Run a code reference, as per "$t-<gt"run()>, but also catching any "die()" calls within the code reference. Returns "undef" if no "die()" call was executed and $@ was unset, or the value of $@ if it was set. (The timeout event doesn't count as a "die()".) $t->timed_out() Returns 1 if the most recent code executed in "run()" timed out, or "undef" if it did not. $t->reset() If called within a "run()" code reference, causes the current alarm timer to be restored to its original setting (useful after our alarm setting was clobbered by some underlying module). perl v5.16.3 2011-06-06 Mail::SpamAssassin::Timeout(3)
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