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Full Discussion: sed in a for loop
Top Forums UNIX for Dummies Questions & Answers sed in a for loop Post 302124401 by marwan on Saturday 30th of June 2007 12:38:24 PM
Old 06-30-2007
sed in a for loop

dear guys,
I want to replace the beginning of some lines in a file by (,)
The sequence number of lines is located in a file named numbers
so, i used this simple script to do so, but it didn't work. it does'nt recognize the $j in the command sed

#! /bin/sh
for j in `cat numbers`
do
sed '$j s/^/,/' file
done

so what's wrong?!
thanks
 

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TAIL(1) 						      General Commands Manual							   TAIL(1)

NAME
tail - deliver the last part of a file SYNOPSIS
tail [ +-number[lbc][rf] ] [ file ] tail [ -fr ] [ -n nlines ] [ -c ncharacters ] [ file ] DESCRIPTION
Tail copies the named file to the standard output beginning at a designated place. If no file is named, the standard input is copied. Copying begins at position +number measured from the beginning, or -number from the end of the input. Number is counted in lines, 1K blocks or characters, according to the appended flag or Default is -10l (ten ell). The further flag causes tail to print lines from the end of the file in reverse order; (follow) causes tail, after printing to the end, to keep watch and print further data as it appears. The second syntax is that promulgated by POSIX, where the numbers rather than the options are signed. EXAMPLES
tail file Print the last 10 lines of a file. tail +0f file Print a file, and continue to watch data accumulate as it grows. sed 10q file Print the first 10 lines of a file. SOURCE
/sys/src/cmd/tail.c BUGS
Tails relative to the end of the file are treasured up in a buffer, and thus are limited in length. According to custom, option +number counts lines from 1, and counts blocks and characters from 0. TAIL(1)
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