Sponsored Content
Full Discussion: subtraction from date
Top Forums UNIX for Dummies Questions & Answers subtraction from date Post 302122211 by Shell_Life on Tuesday 19th of June 2007 04:20:26 PM
Old 06-19-2007
Maria,
Date calculation can be very involved as you have to consider
end of month, end of year, leap year, etc.
Here is a thread that can help you in this issue:
https://www.unix.com/answers-to-frequ...rithmetic.html
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Date Subtraction in KSH

I need to figure out the numeric representation of the previous month (in an automated monthly-running script) so that I may append it to a filename. I have tried statements such as variable=`date +%m -1` (and several variations) but with no success. I have also tried simply assigning the value... (3 Replies)
Discussion started by: mharley
3 Replies

2. Linux

date subtraction(URGENT)

Hi all, I need the date subtraction fuctionality using shell commands. For example: date1:Wed Apr 5 08:35:21 IST 2006 date2:Tue Apr 4 10:35:44 IST 2006 I need the date subtraction result like " 22 hours 23 seconds". Please guide me to complete this task. Can you please help me ASAP. ... (3 Replies)
Discussion started by: uday123
3 Replies

3. Shell Programming and Scripting

awk subtraction

hi i have file 1 as follows: 6 7 8 9 10 i have file 2 as follows: 5 5 5 5 5 i want file 3 as follows: (4 Replies)
Discussion started by: npatwardhan
4 Replies

4. Shell Programming and Scripting

Date subtraction

hi, i set up a script on my server to do a particular task once files from an external system are ftpd in the format compaq_20100110 (YYDDMM). Interestingly, the source of ftp is sending the files in the format e.g 20100109 i.e. previous date and for some reason this fails.kindly see my script... (2 Replies)
Discussion started by: bigtejus
2 Replies

5. Shell Programming and Scripting

use of uninitialized value in subtraction

Hallo all i am trying to execute this script ............... But this is throwing the error...... use of uninitialized value in subtraction in at icd_convert.pl line 156 use of uninitialized value in subtraction in at icd_convert.pl line 157 use of uninitialized value in subtraction in at... (1 Reply)
Discussion started by: suvenduperl
1 Replies

6. Shell Programming and Scripting

Date Subtraction with time.

HI gurus... I have a PERL file that help me extract the date and time of the file. The format of this is: yyyymmddhhmmss. Example: 20100430070935 (April 30 2010 07:09:35) How can i subtract the acquired time from system's time..?? The answer... (6 Replies)
Discussion started by: bankimmehta
6 Replies

7. Shell Programming and Scripting

Subtraction

Hi #!/bin/sh month=`date +%m` year=`date +%Y` echo $month a=02 # Retaining Data for Current and Previous Month lmonth=`expr $month - $a` if test "$lmonth" = "0" then lmonth=12 year=`expr $year - 1` fi echo $year echo $lmonth The output is (3 Replies)
Discussion started by: Abhayman
3 Replies

8. Shell Programming and Scripting

Subtraction using arrays

Hello all . I have two arrays. ${ARRAY_MOUNT_POINT_CAPACITY} ${ARRAY_MOUNT_POINT_CAPACITY}. Whats the synatx of subtracting their values , placing them in variable V1 and then echoeing it ??? Ive tried expr and let ...gives me ./test_code.sh: difference: bad number (3 Replies)
Discussion started by: Junaid Subhani
3 Replies

9. Shell Programming and Scripting

Need Help on date subtraction

I have dates as follows in a file 20121029135649 20121029135721 20121030091540 20121030093420 20121030094340 20121030095427 20121030095856 20121030100104 20121030100251 All these dates are in sorted order. I need to find out the difference between the dates as follows 2nd row... (6 Replies)
Discussion started by: meetsriharsha
6 Replies

10. UNIX for Dummies Questions & Answers

Date Subtraction

Hello All, I am a newbie to unix shell scripting and need to write a script that displays the difference between two variables that stores date value. For example, F1=`ls -ltr file1* | tail -1 |tr -s ' ' |cut -d' ' -f6,7,8` F2=`ls -ltr file2* | tail -1 |tr -s ' ' |cut -d' ' -f6,7,8` F1... (3 Replies)
Discussion started by: priyaa2010
3 Replies
CALENDAR(3)						   BSD Library Functions Manual 					       CALENDAR(3)

NAME
easterg, easterog, easteroj, gdate, jdate, ndaysg, ndaysj, week, weekday -- Calendar arithmetic for the Christian era LIBRARY
Calendar Arithmetic Library (libcalendar, -lcalendar) SYNOPSIS
#include <calendar.h> struct date * easterg(int year, struct date *dt); struct date * easterog(int year, struct date *dt); struct date * easteroj(int year, struct date *dt); struct date * gdate(int nd, struct date *dt); struct date * jdate(int nd, struct date *dt); int ndaysg(struct date *dt); int ndaysj(struct date *dt); int week(int nd, int *year); int weekday(int nd); DESCRIPTION
These functions provide calendar arithmetic for a large range of years, starting at March 1st, year zero (i.e., 1 B.C.) and ending way beyond year 100000. Programs should be linked with -lcalendar. The functions easterg(), easterog() and easteroj() store the date of Easter Sunday into the structure pointed at by dt and return a pointer to this structure. The function easterg() assumes Gregorian Calendar (adopted by most western churches after 1582) and the functions easterog() and easteroj() compute the date of Easter Sunday according to the orthodox rules (Western churches before 1582, Greek and Russian Orthodox Church until today). The result returned by easterog() is the date in Gregorian Calendar, whereas easteroj() returns the date in Julian Calendar. The functions gdate(), jdate(), ndaysg() and ndaysj() provide conversions between the common "year, month, day" notation of a date and the "number of days" representation, which is better suited for calculations. The days are numbered from March 1st year 1 B.C., starting with zero, so the number of a day gives the number of days since March 1st, year 1 B.C. The conversions work for nonnegative day numbers only. The gdate() and jdate() functions store the date corresponding to the day number nd into the structure pointed at by dt and return a pointer to this structure. The ndaysg() and ndaysj() functions return the day number of the date pointed at by dt. The gdate() and ndaysg() functions assume Gregorian Calendar after October 4, 1582 and Julian Calendar before, whereas jdate() and ndaysj() assume Julian Calendar throughout. The two calendars differ by the definition of the leap year. The Julian Calendar says every year that is a multiple of four is a leap year. The Gregorian Calendar excludes years that are multiples of 100 and not multiples of 400. This means the years 1700, 1800, 1900, 2100 are not leap years and the year 2000 is a leap year. The new rules were inaugurated on October 4, 1582 by deleting ten days following this date. Most catholic countries adopted the new calendar by the end of the 16th century, whereas others stayed with the Julian Calendar until the 20th century. The United Kingdom and their colonies switched on September 2, 1752. They already had to delete 11 days. The function week() returns the number of the week which contains the day numbered nd. The argument *year is set with the year that contains (the greater part of) the week. The weeks are numbered per year starting with week 1, which is the first week in a year that includes more than three days of the year. Weeks start on Monday. This function is defined for Gregorian Calendar only. The function weekday() returns the weekday (Mo = 0 .. Su = 6) of the day numbered nd. The structure date is defined in <calendar.h>. It contains these fields: int y; /* year (0000 - ????) */ int m; /* month (1 - 12) */ int d; /* day of month (1 - 31) */ The year zero is written as "1 B.C." by historians and "0" by astronomers and in this library. SEE ALSO
ncal(1), strftime(3) STANDARDS
The week number conforms to ISO 8601: 1988. HISTORY
The calendar library first appeared in FreeBSD 3.0. AUTHORS
This manual page and the library was written by Wolfgang Helbig <helbig@FreeBSD.org>. BUGS
The library was coded with great care so there are no bugs left. BSD
November 29, 1997 BSD
All times are GMT -4. The time now is 09:37 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy