I am trying to find socail security numbers in files in (and under) a specific directory and output a list of the files where they are found... the format would be with no dashes just 9 numeric characters in a row.
I have tried this:
find /DirToLookIn -exec grep '\{9\}' /dev/null {} \; >>... (1 Reply)
I have a directory (and many sub dirs beneath) on AIX system, containing thousands of file. I'm looking to get a list of all directory containing "*.pdf" file.
I know basic syntax of find command, but it gives me list of all pdf files, which numbers in thousands. All I need to know is, which... (4 Replies)
Hi,
I need to go through all the files on my system and build a list/output file with the paths of all files where the first two characters within the file match an expression.
I know I can use something like
find . | xargs cut -b1-2
or
find . -exec cut -b1-2 {} \;
to get the characters... (3 Replies)
I will be very grateful if someone can help me with bash shell script that does the following:
I have a list of filenames:
A01_155716
A05_155780
A07_155812
A09_155844
A11_155876
that are kept in different sub directories within my current directory. I want to find these files and copy... (3 Replies)
counter=0;
while read line;
do ] && let counter=counter+1; done < input_file.txt
echo $counter
The above code is reading a file line by line and checking whether the filenames mentioned in the file exist or not .
At present the o/p is value of counter
I want to echo out the name of... (5 Replies)
Hi,
I am looking for a command or script which should list out the files that uses database password 'June1232011'.
I know where the files are located (path) .Since there are too many files exist in the directory, i want to find out the files that uses this password.
It would be a... (10 Replies)
find list of files modified for a given day ?
if i have 10 files in my directory, i have modified only 5 ... how to display only modified files ? (1 Reply)
I need to find a word '% Retail by State' in the folder /usr/sas/reports/RetailSalesTaxallocation.
When I tried like below,
-bash-4.1$ cd /usr/sas/reports/RetailSalesTaxallocation
-bash-4.1$ find ./ -name % Retail by State
find: paths must precede expression: Retail
Usage: find ... (10 Replies)
Helo
Is there a better way to search within a list of subfolders :
A_START_PATH="/data_1/data_2"
#
# dir2, dir3, dir6, ..... dir59 exists
#
A_LIST="$A_START_PATH/dir1 $A_START_PATH/dir4 $A_START_PATH/dir5"
find "$A_LIST" -type f -name"*.txt"
Now searching for all files in any subdirs... (2 Replies)
Discussion started by: jcdole
2 Replies
LEARN ABOUT DEBIAN
shell-quote
SHELL-QUOTE(1p) User Contributed Perl Documentation SHELL-QUOTE(1p)NAME
shell-quote - quote arguments for safe use, unmodified in a shell command
SYNOPSIS
shell-quote [switch]... arg...
DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands
or files with embedded white space or shell globbing characters safely. Here are a few examples.
EXAMPLES
ssh preserving args
When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and
passes them to "$SHELL -c". This doesn't work as intended:
ssh host touch 'hi there' # fails
It creates 2 files, hi and there. Instead, do this:
cmd=`shell-quote touch 'hi there'`
ssh host "$cmd"
This gives you just 1 file, hi there.
process find output
It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to
split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote:
eval set -- `find -type f -print0 | xargs -0 shell-quote --`
debug shell scripts
shell-quote is better than echo for debugging shell scripts.
debug() {
[ -z "$debug" ] || shell-quote "debug:" "$@"
}
With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can.
save a command for later
shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command
you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are
things the user can't pass through), you can do something like this:
user_switches=
while [ $# != 0 ]
do
case x$1 in
x--pass-through)
[ $# -gt 1 ] || die "need an argument for $1"
user_switches="$user_switches "`shell-quote -- "$2"`
shift;;
# process other switches
esac
shift
done
# later
eval "shell-quote some-command $user_switches my args"
OPTIONS --debug
Turn debugging on.
--help
Show the usage message and die.
--version
Show the version number and exit.
AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions.
AUTHOR
Roderick Schertler <roderick@argon.org>
perl v5.8.4 2005-05-03 SHELL-QUOTE(1p)