Hi,
I am trying to do achieving of files by months.
find /test -name \*.* -mtime +30
will give me the result of all modified files after 30 days.
But lets say i want to list all files that is modified in last months... what is the command to do it?
Thanks! (13 Replies)
I am trying to write a script that shows every Friday in a month.
I used
cal $1 $2 | grep -v "^$" | awk '{print $6}'
It doesn't work for the frist week of Friday because calendar command output has some spaces in the first line and awk '{print $6}' doesn't work. Anybody help
me with this... (3 Replies)
I needed a cron job to run on the second to last friday of every month. Our servers are running HP-UX, and the HP-UX date command is pretty basic and does not have all of the fancy options that Linux date command does, and it does not have the ability at all to return future dates. So I had to... (0 Replies)
Hi Expert
Please help me to set a cron job schedule,
Ihave a job that run every 3rd Friday of the month at 1030am.
I tried to set up like this, but the job still runs every friday at 1030am.
I want the job to run every 3rd Friday of the month at 1030am only
30 10 15,16,17,18,19,20,21... (2 Replies)
Hi All,
I need to find last two files for the month.
lets say there are following files in directory
-rwxr-xr-x 1 user userg 1596 Mar 19 15:43 c.txt
-rwxr-xr-x 1 user userg 1596 Mar 21 15:43 d.txt
-rwxr-xr-x 1 user userg 1596 Mar 22 15:43 f.txt
-rwxr-xr-x 1... (14 Replies)
Hi,
I want two dates one will be the current date and the other one will be just one month before. Say if current month is 11/4/2014 then the other date should be 11/3/2014.
#!/bin/ksh
currentDtae=`date`
oneMonthBefore= ?
I dont know how to do it. Went through some of the related threads... (15 Replies)
Hello,
I need to find the date of next first Friday of the month and set as a variable in a bash script
ie -
FIRSTFRIDAY=$(date -dfirst-friday +%d)
I know date -dfirst-friday doesn't work, but unsure if I can use this / cal + awk or something else to find the right date of the... (7 Replies)
Discussion started by: summerdays
7 Replies
LEARN ABOUT CENTOS
cal
CAL(1) User Commands CAL(1)NAME
cal - display a calendar
SYNOPSIS
cal [options] [[[day] month] year]
DESCRIPTION
cal displays a simple calendar. If no arguments are specified, the current month is displayed.
OPTIONS -1, --one
Display single month output. (This is the default.)
-3, --three
Display prev/current/next month output.
-s, --sunday
Display Sunday as the first day of the week.
-m, --monday
Display Monday as the first day of the week.
-j, --julian
Display Julian dates (days one-based, numbered from January 1).
-y, --year
Display a calendar for the current year.
-V, --version
Display version information and exit.
-h, --help
Display help screen and exit.
PARAMETERS
A single parameter specifies the year (1 - 9999) to be displayed; note the year must be fully specified: cal 89 will not display a calendar
for 1989.
Two parameters denote the month (1 - 12) and year.
Three parameters denote the day (1-31), month and year, and the day will be highlighted if the calendar is displayed on a terminal. If no
parameters are specified, the current month's calendar is displayed.
A year starts on Jan 1. The first day of the week is determined by the locale.
The Gregorian Reformation is assumed to have occurred in 1752 on the 3rd of September. By this time, most countries had recognized the ref-
ormation (although a few did not recognize it until the early 1900's). Ten days following that date were eliminated by the reformation, so
the calendar for that month is a bit unusual.
HISTORY
A cal command appeared in Version 6 AT&T UNIX.
AVAILABILITY
The cal command is part of the util-linux package and is available from ftp://ftp.kernel.org/pub/linux/utils/util-linux/.
util-linux June 2011 CAL(1)