Hi,
I need a regular expression grepping all lines starting with '*' followed by a VARIOUS number of blanks and then followed by the string 'Runjob=1'.
I tried that code, but it doesn't work:
grep -i '*'+'Runjob=1' INPUT_FILE >>OUTPUT_FILE
Can someone help me?
Thanks (8 Replies)
Hey, I found a way to print the lines which is just before a regular expression, not including the expression.
sed -n '/regexp/{n;p;}' myfile
Now I'm looking for a way to print all lines, exept the regular expression and also the line before the same regular expression.
Use code tags. (1 Reply)
CA_RELEASE has a value of 6. I need to check if that this is a numeric value. if not error.
source $CA_VERSION_DATA
if * ]
then
echo "CA_RELESE $CA_RELEASE is invalid"
exit -1
fi
+ source /etc/ncgl/ca_version_data
++ CA_PRODUCT_ID=samxts
++ CA_RELEASE=6
++ CA_WEEK_NO=7
++... (3 Replies)
I would like to print 3 lines after a regular expression is found in the logfile. I'm using the following code:
grep -n "$reg_exp" file.txt |while read LINE ;do i=$(echo $LINE |cut -d':' -f1 ) ;sed -n "$i,$(($i+3))p" file.txt ;done
The above code things works fine,but sometimes gives erroneous... (3 Replies)
Hi all,
How am I read a file, find the match regular expression and overwrite to the same files.
open DESTINATION_FILE, "<tmptravl.dat" or die "tmptravl.dat";
open NEW_DESTINATION_FILE, ">new_tmptravl.dat" or die "new_tmptravl.dat";
while (<DESTINATION_FILE>)
{
# print... (1 Reply)
I have a very large file (over 700 million lines) that has some lines that I need to delete. An example of 5 lines of the file:
HS4_80:8:2303:19153:193032 153 k80:138891
HS4_80:8:2105:5544:43174 89 k88:81949
165 k88:81949 323 0 * = 323 0 ... (6 Replies)
So the tag for this forum says all newbies welcome...
All I want to do is go through my file and find lines which contain a given string of characters then replace these with a blank line. I really tried to find a simple command to do this but failed.
Here's what I did come up with though:
... (2 Replies)
Hello All,
I'm trying to extract the lines between two consecutive elements of an array from a file.
My array looks like:
problem_arr=(PRS111 PRS213 PRS234)
j=0
while } ]
do
k=`expr $j + 1`
sed -n "/${problem_arr}/,/${problem_arr}/p" problemid.txt
---some operation goes... (11 Replies)
Using a regular expression, I would like multiple lines to be matched.
By default, a period (.) matches any character except newline. However, (?s) and /s modifiers are supposed to force . to accept a newline and to match any character including a newline.
However, the following two perl... (4 Replies)
Discussion started by: LessNux
4 Replies
LEARN ABOUT PLAN9
regexp
REGEXP(6) Games Manual REGEXP(6)NAME
regexp - regular expression notation
DESCRIPTION
A regular expression specifies a set of strings of characters. A member of this set of strings is said to be matched by the regular
expression. In many applications a delimiter character, commonly bounds a regular expression. In the following specification for regular
expressions the word `character' means any character (rune) but newline.
The syntax for a regular expression e0 is
e3: literal | charclass | '.' | '^' | '$' | '(' e0 ')'
e2: e3
| e2 REP
REP: '*' | '+' | '?'
e1: e2
| e1 e2
e0: e1
| e0 '|' e1
A literal is any non-metacharacter, or a metacharacter (one of .*+?[]()|^$), or the delimiter preceded by
A charclass is a nonempty string s bracketed [s] (or [^s]); it matches any character in (or not in) s. A negated character class never
matches newline. A substring a-b, with a and b in ascending order, stands for the inclusive range of characters between a and b. In s,
the metacharacters an initial and the regular expression delimiter must be preceded by a other metacharacters have no special meaning and
may appear unescaped.
A matches any character.
A matches the beginning of a line; matches the end of the line.
The REP operators match zero or more (*), one or more (+), zero or one (?), instances respectively of the preceding regular expression e2.
A concatenated regular expression, e1e2, matches a match to e1 followed by a match to e2.
An alternative regular expression, e0|e1, matches either a match to e0 or a match to e1.
A match to any part of a regular expression extends as far as possible without preventing a match to the remainder of the regular expres-
sion.
SEE ALSO awk(1), ed(1), sam(1), sed(1), regexp(2)REGEXP(6)