Hi,
I am working on a command that replaces some occurrences of quotation marks in file. The quotation mark cannot be the first or the last character in line and cannot be preceded or followed by a comma.
I am not an expert in regular expressions, but I managed to create the following... (2 Replies)
Hi
Can anyone provide me the replacement of sed with xargs perl syntax for the below
sed -e :a -e '/;$/!N;s/\n//; ta' -e 's/;$//'
This should be without looping has to take minimal time for search (0 Replies)
I've been tasked with converting our software from strictly an IPv4 environment to handling both IPv4 and IPv6. I'm very nearly done and everything seems to be progressing just fine. There's just one thing that's been nagging me for a while now, so I thought I'd enquire about this.
I've read... (1 Reply)
There is a requirement that i need to replaced a pattern by another pattern in all the files in my entire file system. there are 1000s of file in the system. let the pattern is "calcuta". i have to replace this pattern by "kolkata" in all those files which contain "calcuta".
I am only able to... (12 Replies)
Hi All,
I have below file which has data in below format.
#$ | AB_100
| AB_300
()| AB_4
@*(% | AB-789
i want o/p as below format.
| AB_100
| AB_300
| AB_4
| AB-789
So here there is no standard format.
How we can achieve the same in unix ?
Regards, (3 Replies)
Hi,
i have a file with lines,
file.txt
-------
test is fun
testing is better
I need to replace 'test' to 'develop' and i used,
a=test
b=develop
sed "s,$a,$b,g" -------- but i see the word 'testing' is also replaced. Need some solution. Is there any way i could replace only 'test' ? (4 Replies)
Hi
pls help me for below;
i have a file .content is :
===================
uid,pcsPricingPlan,refPcsQosProfName
821910002022,smartlimit,SGSNQOS1
i have to replace the value of uid and pricingplan by a unix script.
may be the value would be next line or any where in the file.
pls... (9 Replies)
I recently picked up an HP9000 server running HPUX. I would like to replace the CRT terminal console with something I can use a flat panel monitor. Any suggestions would be greatly appreciated. (1 Reply)
Hello,
I am getting below error in fmadm output. This server is not in support, so can't reach them. Is it showing that motherboard is faulty and should be replaced ? It was rebooted a week back and then, there were no errors
# fmadm faulty
--------------- ------------------------------------ ... (1 Reply)
Discussion started by: solaris_1977
1 Replies
LEARN ABOUT PHP
datefmt_set_lenient
DATEFMT_SET_LENIENT(3) 1 DATEFMT_SET_LENIENT(3)IntlDateFormatter::setLenient - Set the leniency of the parser
Object oriented style
SYNOPSIS
public bool IntlDateFormatter::setLenient (bool $lenient)
DESCRIPTION
Procedural style
bool datefmt_set_lenient (IntlDateFormatter $fmt, bool $lenient)
Define if the parser is strict or lenient in interpreting inputs that do not match the pattern exactly. Enabling lenient parsing allows
the parser to accept otherwise flawed date or time patterns, parsing as much as possible to obtain a value. Extra space, unrecognized
tokens, or invalid values ("February 30th") are not accepted.
PARAMETERS
o $fmt
- The formatter resource
o $lenient
- Sets whether the parser is lenient or not, default is TRUE (lenient).
RETURN VALUES
Returns TRUE on success or FALSE on failure.
EXAMPLES
Example #1
datefmt_set_lenient(3) example
<?php
$fmt = datefmt_create(
'en_US',
IntlDateFormatter::FULL,
IntlDateFormatter::FULL,
'America/Los_Angeles',
IntlDateFormatter::GREGORIAN,
'dd/MM/yyyy'
);
echo 'lenient of the formatter is : ';
if ($fmt->isLenient()) {
echo 'TRUE';
} else {
echo 'FALSE';
}
datefmt_parse($fmt, '35/13/1971');
echo "
Trying to do parse('35/13/1971').
Result is : " . datefmt_parse($fmt, '35/13/1971');
if (intl_get_error_code() != 0) {
echo "
Error_msg is : " . intl_get_error_message();
echo "
Error_code is : " . intl_get_error_code();
}
datefmt_set_lenient($fmt, false);
echo "
Now lenient of the formatter is : ";
if ($fmt->isLenient()) {
echo 'TRUE';
} else {
echo 'FALSE';
}
datefmt_parse($fmt, '35/13/1971');
echo "
Trying to do parse('35/13/1971').
Result is : " . datefmt_parse($fmt, '35/13/1971');
if (intl_get_error_code() != 0) {
echo "
Error_msg is : ".intl_get_error_message();
echo "
Error_code is : ".intl_get_error_code();
}
?>
Example #2
OO example
<?php
$fmt = new IntlDateFormatter(
'en_US',
IntlDateFormatter::FULL,
IntlDateFormatter::FULL,
'America/Los_Angeles',
IntlDateFormatter::GREGORIAN,
'dd/MM/yyyy'
);
echo 'lenient of the formatter is : ';
if ($fmt->isLenient()) {
echo 'TRUE';
} else {
echo 'FALSE';
}
$fmt->parse('35/13/1971');
echo "
Trying to do parse('35/13/1971').
Result is : " . $fmt->parse('35/13/1971');
if (intl_get_error_code() != 0) {
echo "
Error_msg is : " . intl_get_error_message();
echo "
Error_code is : " . intl_get_error_code();
}
$fmt->setLenient(FALSE);
echo "
Now lenient of the formatter is : ";
if ($fmt->isLenient()) {
echo 'TRUE';
} else {
echo 'FALSE';
}
$fmt->parse('35/13/1971');
echo "
Trying to do parse('35/13/1971').
Result is : " . $fmt->parse('35/13/1971');
if (intl_get_error_code() != 0) {
echo "
Error_msg is : " . intl_get_error_message();
echo "
Error_code is : " . intl_get_error_code();
}
?>
The above example will output:
lenient of the formatter is : TRUE
Trying to do parse('35/13/1971').
Result is : 66038400
Now lenient of the formatter is : FALSE
Trying to do parse('35/13/1971').
Result is :
Error_msg is : Date parsing failed: U_PARSE_ERROR
Error_code is : 9
SEE ALSO datefmt_is_lenient(3), datefmt_create(3).
PHP Documentation Group DATEFMT_SET_LENIENT(3)