05-17-2007
Quote:
Originally Posted by dLloydm
There is one more thing I would like to verify. The course has the following question:
What do you think is the output of the following piece of code?
((x = 2#1101 & 2#110))
((y = ~x))
print - $y
The answer given is 11, as in decimal eleven or 2#1011.
From what I understand I think the answer should be -5 as in -2#101.
You are correct:
$ ((x = 2#1101 & 2#110))
$ ((y = ~x))
$ print - $y
-5
$
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LEARN ABOUT DEBIAN
datetime::format::epoch::unix
DateTime::Format::Epoch::Unix(3pm) User Contributed Perl Documentation DateTime::Format::Epoch::Unix(3pm)
NAME
DateTime::Format::Epoch::Unix - Convert DateTimes to/from Unix epoch seconds
SYNOPSIS
use DateTime::Format::Epoch::Unix;
my $dt = DateTime::Format::Epoch::Unix->parse_datetime( 1051488000 );
# 2003-04-28T00:00:00
DateTime::Format::Epoch::Unix->format_datetime($dt);
# 1051488000
my $formatter = DateTime::Format::Epoch::Unix->new();
my $dt2 = $formatter->parse_datetime( 1051488000 );
$formatter->format_datetime($dt2);
DESCRIPTION
This module can convert a DateTime object (or any object that can be converted to a DateTime object) to the number of seconds since the
Unix epoch.
METHODS
Most of the methods are the same as those in DateTime::Format::Epoch. The only difference is the constructor.
o new()
Constructor of the formatter/parser object. It has no parameters.
SUPPORT
Support for this module is provided via the datetime@perl.org email list. See http://lists.perl.org/ for more details.
AUTHOR
Eugene van der Pijll <pijll@gmx.net>
COPYRIGHT
Copyright (c) 2003 Eugene van der Pijll. All rights reserved. This program is free software; you can redistribute it and/or modify it
under the same terms as Perl itself.
SEE ALSO
DateTime
datetime@perl.org mailing list
perl v5.10.1 2007-12-03 DateTime::Format::Epoch::Unix(3pm)