hi,
I have a big file that contains datas since 4 years ago.
I need re-create this file but just lines that are 13 months ago from today.
see what I have: ( I have a file.ksh that calls this file.scl ok !!)
======== file.scl ================
/STATISTICS=stderr
/STABLE
/NODUPLICATES... (3 Replies)
hi,
I have a big file that contains datas since 4 years ago.
I need re-create this file but just lines that are 13 months ago from today.
see what I have: ( I have a file.ksh that calls this file.scl ok !!)
======== file.scl ================
/STATISTICS=stderr
/STABLE
/NODUPLICATES... (4 Replies)
I know I can't schedule this in cron and would have to write a wrapper around my script and schedule it in cron ....but not sure how do to this?
How do I exclude Monday if the 2nd day of the month falls on a Monday?
Thanks.
I tried this:
0 0 2 * 0,2-6 command
And I know this doesnt... (2 Replies)
Hello,
I wanted to display the month for previous day date. Like, today date is 18-Nov-2008. So the previous date is 17-Nov-2008. The output should be November.
If the today date is 1-DEC-2008, then output should be NOVEMBER.
If the today date is 1-JAN-2008, then output should be DECEMBER.... (4 Replies)
Hello Experts,
I have a script which i want to run the on last day of every month.
let say I have backup.sh script which i want to run it every month last day.
Can anyone please help :confused:
thanks (4 Replies)
Hi,
I need to schedule a script to run on the 3rd tuesday of every odd months at 9 am.
min, hour would be - 0 9
month would be - 1,3,5,7,9,11
Can someone suggest how I can schedule it to 3rd tuesday?
Thanks. (8 Replies)
Hi Team,
We have a requirement as follows.
If a date 20141220 as parameter to the script, then the script has to return the output as 20141219.
i.e given date - 1.
The requirement is simple. But it should satisfy leap year, the months having 31 and 30 days, the date in which day light... (9 Replies)
I am looking for a unix script which could run a job on 2, 4 and 7 working day of the month.
if the days are falling on the saturday/sunday. it should run on the next day.
Thank you.. (9 Replies)
Hi, I need the first & last day of a month from any given date. For better understanding, if i need to back-fill data for date 07/20/2019 i.e July 20 2019, i need the first & last day has 07/01/2019 - 07/31/2019. FYI: I'm using GIT BASH terminal.
sample code:
export DT=$(date --date='6 days... (2 Replies)
Discussion started by: Rocky975583
2 Replies
LEARN ABOUT PHP
datetime.add
DATETIME.ADD(3) 1 DATETIME.ADD(3)DateTime::add - Adds an amount of days, months, years, hours, minutes and seconds to a DateTime object
Object oriented style
SYNOPSIS
public DateTime DateTime::add (DateInterval $interval)
DESCRIPTION
Procedural style
DateTime date_add (DateTime $object, DateInterval $interval)
Adds the specified DateInterval object to the specified DateTime object.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $interval
- A DateInterval object
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
EXAMPLES
Example #1
DateTime.add(3) example
Object oriented style
<?php
$date = new DateTime('2000-01-01');
$date->add(new DateInterval('P10D'));
echo $date->format('Y-m-d') . "
";
?>
Procedural style
<?php
$date = date_create('2000-01-01');
date_add($date, date_interval_create_from_date_string('10 days'));
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2000-01-11
Example #2
Further DateTime.add(3) examples
<?php
$date = new DateTime('2000-01-01');
$date->add(new DateInterval('PT10H30S'));
echo $date->format('Y-m-d H:i:s') . "
";
$date = new DateTime('2000-01-01');
$date->add(new DateInterval('P7Y5M4DT4H3M2S'));
echo $date->format('Y-m-d H:i:s') . "
";
?>
The above example will output:
2000-01-01 10:00:30
2007-06-05 04:03:02
Example #3
Beware when adding months
<?php
$date = new DateTime('2000-12-31');
$interval = new DateInterval('P1M');
$date->add($interval);
echo $date->format('Y-m-d') . "
";
$date->add($interval);
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2001-01-31
2001-03-03
NOTES DateTime.modify(3) is an alternative when using PHP 5.2.
SEE ALSO DateTime.sub(3), DateTime.diff(3), DateTime.modify(3).
PHP Documentation Group DATETIME.ADD(3)