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Top Forums Shell Programming and Scripting regexp to get first line of string Post 302116754 by jonas.gabriel on Tuesday 8th of May 2007 09:46:40 AM
Old 05-08-2007
Question regexp to get first line of string

Hi everybody

Code:
for file in *
#Bash performs filename expansion
#+ on expressions that globbing recognizes.
do
	
	output="`grep -n "$1" "$file"`"
	echo "$file: `expr "$output" : '\(^.*$\)'`"

done

In the above bash script segment, I try to print just the first line of string named output.

I've got a problem with the regexp. It returns the full string which is multilined.

Thank you in advance for any help
 

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ZGREP(1)						      General Commands Manual							  ZGREP(1)

NAME
zgrep - search possibly compressed files for a regular expression SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename... DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code: (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep. If the GREP environment variable is set, zgrep uses it as the grep program to be invoked. EXIT CODE
2 - An option that is not supported was specified. AUTHOR
Charles Levert (charles@comm.polymtl.ca) SEE ALSO
grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1) ZGREP(1)
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