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Top Forums UNIX for Dummies Questions & Answers Extracting Filename from Fullpath Post 302114936 by cfajohnson on Thursday 19th of April 2007 01:36:40 PM
Old 04-19-2007
Quote:
Originally Posted by njoshi
Hi,
Any help on this would be very appreciated.

I capture the full path & filename in a variable like (varFile=/home/user/extfile.txt). Now in my shell script I have to use only the filename part i.e. extfile.txt. How do I extract only the filename part from the variable?

Use shell parameter expansion:

Code:
filename=${varFile##*/}

 

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CHGRP(3)								 1								  CHGRP(3)

chgrp - Changes file group

SYNOPSIS
bool chgrp (string $filename, mixed $group) DESCRIPTION
Attempts to change the group of the file $filename to $group. Only the superuser may change the group of a file arbitrarily; other users may change the group of a file to any group of which that user is a member. PARAMETERS
o $filename - Path to the file. o $group - A group name or number. RETURN VALUES
Returns TRUE on success or FALSE on failure. EXAMPLES
Example #1 Changing a file's group <?php $filename = 'shared_file.txt'; $format = "%s's Group ID @ %s: %d "; printf($format, $filename, date('r'), filegroup($filename)); chgrp($filename, 8); clearstatcache(); // do not cache filegroup() results printf($format, $filename, date('r'), filegroup($filename)); ?> NOTES
Note This function will not work on remote files as the file to be examined must be accessible via the server's filesystem. Note When safe mode is enabled, PHP checks whether the files or directories being operated upon have the same UID (owner) as the script that is being executed. SEE ALSO
chown(3), chmod(3). PHP Documentation Group CHGRP(3)
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